Answer:
The probability that the pirate misses the captain's ship but the captain hits = 0.514
Step-by-step explanation:
Let A be the event that the captain hits the pirate ship
The probability of the captain hitting the pirate ship, P(A) = 3/5
Let B be the event that the pirate hits the captain's ship
The probability of the pirate hitting the captain's ship P(B) = 1/7
The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)
P'(B) = 1 - 1/7 = 6/7
The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7
= 0.514
Answer:
45.1feet
Step-by-step explanation:
Given the following
∠I=90°
∠G=62°, and
GH = 96 feet = Hypotenuse
Required
IG = Adjacent side
Using the SOH CAH TOA identity
Cos theta = Adj/hyp
Cos 62 =IG/96
IG = 96cos62
IG = 96(0.4695)
IG = 45.1feet
Hence the length of IG to the nearest tenth is 45.1feet
Answer:
(21, 17 )
Step-by-step explanation:
Using the midpoint formula and equating to the coordinates of the midpoint.
Let endpoint 2 have coordinates (x, y ), then
0.5(x - 3) = 9 ( multiply both sides by 2 )
x - 3 = 18 ( add 3 to both sides )
x = 21
and
0.5(y - 5) = 6 ( multiply both sides by 2 )
y - 5 = 12 ( add 5 to both sides )
y = 17
endpoint 2 = (21, 17 )
The answer to the problem is 17
Are you asking how to solve this equation?
