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luda_lava [24]
3 years ago
12

A driveway is 60-feet long by 6-feet wide. The length and width of the driveway will each be increased by the same number of fee

t. The following expression represents the perimeter of the larger driveway: (x + 60) + (x + 6) + (x + 60) + (x + 6) Which expression is equivalent to the expression for the perimeter of the larger driveway? A) 2(x + 66) B) 4x + 33 C) 4(x + 33) D) 4(x + 132)
Mathematics
2 answers:
Dafna11 [192]3 years ago
6 0

Answer: C) 4(x+33)

Step-by-step explanation:

1. You know that the perimeter of the larger driveway is represented with the following expression given in the problem:

(x+60)+(x+6)+(x+60)+(x+6)

2. When you simplify it and add the like terms, you obtain:

x+60+x+6+x+60+x+6=4x+132

3. Now, you can factor out 4. Therefore, you can write the expression as below:

4(x+33)

4. So, you can conclude that the answer is the option C.

BabaBlast [244]3 years ago
4 0

Answer:

C)

Step-by-step explanation:

I just took the test and it was right.

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216

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Step-by-step explanation:

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The volume of a pyramid varies jointly with the base area of the pyramid and its height. The volume of one pyramid is 35 cubic i
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6 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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mel-nik [20]

Answer:

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Step-by-step explanation:

8 0
2 years ago
(20 points)
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Answer:

B

Step-by-step explanation:

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3 0
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