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Ipatiy [6.2K]
3 years ago
9

How would you round the number 33 and. 89 to estimate their sum

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0
The answer is going to be 120
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The perimeter of a rectangular park is 300 feet. The length of the park is 50 feet longer than the width.
bixtya [17]

Answer:

85 feet

Step-by-step explanation:

P=2L+2W where L is the length and W is the width. If the length is 50 feet longer than the width, we can write the expression L=50+W. Substituting into P=2L+2W we get P=2(50+W)+2W=100+2W+2W=100+4W. Since P=300, we can say 300=100+4W. Subtracting 100 from each side we get 200=4W. Dividing each side by 4 gives 50=W. Substituting this into L=50+W gives L=50+35=85. The length is 85 feet.

3 0
3 years ago
4. Use the two patterns below. What are the first four ordered pairs formed from
kobusy [5.1K]

Answer:

0,2,4,8

Step-by-step explanation:

:)

7 0
3 years ago
In the first 120 miles over 240 mile journey a truck driver maintained an average speed of 50 mph what was his average featuring
Keith_Richards [23]
The correct answer is 70 MPH because when 50 and 70 are added together and divided by 2, you get 60.
3 0
3 years ago
Read 2 more answers
Please help me answer this
vodka [1.7K]

Answer:


Step-by-step explanation:


8 0
3 years ago
Two dogs run around a circular track 300 m long. One dog runs at a steady rate of 15m per second, the other at a steady rate of
mihalych1998 [28]

Answer:

300 seconds

Step-by-step explanation:

The first dog run at v₁ = 15 m/sec     the second one run at  v₂ = 12 m/sec

we know that  d = v*t  then  t  =  d/v

Then the first dog will take  300/ 12  =  25 seconds to make a turn

The second will take   300 / 15   =   20 seconds to make a turn

Then the first dog in 12 turns 12*25 will be at the start point, and so will the second one at the turn 15.

To check  first dog    12 *  25 = 300

And the second dog 15 * 20 = 300

That means that time required for the two dogs to be at the start point together is

300 seconds, in that time the first dog finished the 12 turns, and the second had ended the 15.

Another procedure to solve this problem is as follows:

between  12  m/sec and  15 m/sec   the minimum common multiple  is 300 ( 300 is the smaller number that accept 12 and 15 as factors         12*15 = 300) Then when time arrives at 300 seconds the two dogs will be again in the starting point

3 0
3 years ago
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