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torisob [31]
3 years ago
12

e) The diagonal of square A, marked off by the red stars, is where the concession stand is located. A local high school band is

performing at the outdoor theater on a summer evening. The band has a school banner that is 40-feet long, and band members would like to hang it across the concession stand to let people know they are performing. Estimate the length of the concession stand to determine if the school banner can fit across the length of the concession stand. Show your work and explain your reasoning.
Mathematics
2 answers:
Elis [28]3 years ago
3 0

Answer:

<h2>60 ft long bc that would leave 10ft on each side of the banner...</h2>

Step-by-step explanation:

<h2>Hopes this helps. Mark as brainlest plz!</h2>
Dovator [93]3 years ago
3 0

Answer:

Solution given:

length [l]=breadth [b]=40ft

Now

length of concession banner[h]=?

we have

perpendicular [p]=base[B]=40ft

by using Pythagoras law

h²=p²+b²

h²=40²+40²

h=√3200

h=40√2

So

<u>the length of the concession stand to determine if the school banner can fit across the length of the concession </u><u>stand</u><u> </u><u>is</u><u> </u><u>4</u><u>0</u><u>√</u><u>2</u><u> </u><u>ft</u><u> </u><u>or</u><u> </u><u>5</u><u>6</u><u>.</u><u>5</u><u>7</u><u>ft</u>

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sdas [7]

Answer :

1

Step-by-step-explanation :

{x}^{2}  + 4x + 5 -  {(x + 2)}^{2}  \\  {x}^{2}  + 4x + 5 - ( {x}^{2}  + 4x + 4)   \\

{x}^{2}  + 4x + 5 -  {x}^{2}  - 4x - 4 =  {x}^{2}  -  {x}^{2}  + 4x - 4x + 5 - 4 = 5 - 4 = 1

8 0
4 years ago
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I need help with this please help!!
aalyn [17]
The line extends to the right, so the answer must be C or D. The dot is not filled in, which means -2 is not included in the solution. Therefore the correct answer is C: x is greater than -2.

Hope this helps.
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3 years ago
Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

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Ivanshal [37]
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