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Triss [41]
2 years ago
12

Which expressions are equivalent to 3p+15

Mathematics
2 answers:
finlep [7]2 years ago
6 0

1 and 2.

7p - 4p + 15

3p + 15

3 (p + 5)

(3 • p) + (3 • 5)

3p + 15

I hope this helps let me know if you need any more help :)

rodikova [14]2 years ago
4 0

Answer:

Left most and the one u selected

Step-by-step explanation:

7p-4p+15 = 3p+15

3(p+5) = 3p + 3 * 5 = 3p + 15

2p-p+15 = p+15

3(p+15) = 3p+45

if correct, pls mark 5 star, thanks, and brainliest!

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A nugget of gold is placed in a graduated cylinder that contains 85 mL of water.the water level rises to 225 mL after the nugget
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Before changes to its management staff, an automobile assembly line operation had a scheduled mean completion time of minutes. T
Sergio [31]

No, we don't have evidence to support that the mean completion time under new management has decreased but we can conclude that it remains at 15.5 minutes.

Given mean of 15.5 minutes , standard deviation of 1.7 minutes, sample size of 90 and sample mean of 15.4 minutes.

We can do the following study for conclusion:

Firstly the null hypothesis is

H_{0}: x=15.5

The alternate hypothesis is

H_{1}: x < 15.5

since the value is less than this is a one tailed test.

Z=x bar-x/d/\sqrt{n}

where x is sample mean and d is standard deviation.

Z=15.4-15.5/1.7/\sqrt{90}

=-0.1/1.7/9.4868

=-0.560

Critical value of Z at 0.1 level of significance

Z=-1.28

We fails to reject the null hypothesis since -0.560>-1,28

Hence we don't have evidence to support that the mean completion time under new management has decreased but we can conclude that it remains at 15.5 minutes.

Learn more about hypothesis at brainly.com/question/11555274

#SPJ4

Question is incomplete. It should include:

mean of 15.5 minutes ,

standard deviation of 1.7 minutes,

sample size of 90

and sample mean of 15.4 minutes.

5 0
1 year ago
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