The Sharps purchased a new sectional. The cost

Mathematics

1 answer:

svet-max [94.6K]2 years ago

6 0

Answer:

$1913.34

Step-by-step explanation:

$1784 (original amount) * 7.25% (sales tax) = $129.34 Tax paid

129.34 + 1784 = Price after tax

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?<br> For which value of x is the inequality 45 - 4x < 14 true?

viktelen [127]

Answer:

7.75

Step-by-step explanation:

You group like terms from the inequality above ie by making the x value stands alone and you can only do this by sending 14 to the left side of the inequality and 4x to the right side. This becomes 45-14 < 4x and that gives you 31 < 4x. Then you divide both side by the number attached to the variable 'x' ie 4. So 31/4 < 4x/4 making x > 31/4 which is 7.75

8 0

2 years ago

A pair of numbers that has the sum of 12 and a difference of eight

anygoal [31]

Answer:

2 ; 10

Step-by-step explanation:

a + B = 12

a - B = 8

a = 12 - B

(12 - B) - B = 8

a = 12 - B

12 - 2B = 8

B = 2

A = 10

7 0

2 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .