Answer: The cost of one rose bush is $7 and the cost of one shrub is also $7
Step-by-step explanation:
The situtation can be represented by the systems of the equations.
10x + 4y = 98 x in this case is the cost of one rose bushes
9x + 9y = 126 y is the cost of one shrub.
Solve the system of equation using the elimination method.
10x +4y = 98
9x + 9y = 126 eliminate the y variable so you will have to multiply 9 on top and -4 down.
9(10x +4) = (98)(9)
-4(9x + 9y) = 126(-4)
You will now have the new two systems of equations
90x +36y = 882
-36x +-36y = -504 Now add the equations
0 + 54x = 378
54x = 378
x= 7
Now we know that the cost of one rose bush is 7 so we will plot it into one of the equations and solve for the cost of one shrub.
90(7) +36y=882
630 +36y = 882
-630 -630
36y = 252
y = 7
Check: 10(7) + 4(7)= 98
70 + 28 = 98
98= 98
so one rose bush is actually 7 dollars the same as 1 shrub.
C. Reflected over the y-axis and translated up 1 unit
Answer:
y=1x(x−6)
Step-by-step explanation:
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Answer:
Sequence 1
Step-by-step explanation:
<u>You need to find the difference between term - the nth term.</u>
<u>The difference / nth term has to to -1/2 (-0.5)</u>
Sequence 1:
-6 * -0.5 = 3 * -0.5 = -3/2 (-1.5) * -0.5 = 3/4 (0.75) * -0.5 = -3/8 (-0.375)
Sequence 2:
4 * -2 = -8 *-2 = 16 * -2 = - 32 * -2 = 64
Sequence 3:
-1/3 ÷ 2 = -1/6 ÷ 2 = 12 ÷ 2 = 24 ÷ 2 = 48
Sequence 4:
400 ÷ -2 = -200 ÷ -2 = 100 ÷ -2 = -50 ÷ -2 = 25
The only sequence with a common ratio of -1/2 is Sequence 1.
