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Natasha_Volkova [10]
2 years ago
9

A bag contains 12 toffees. Kate eats 3 toffees and Josh eats 4 toffees.

Mathematics
2 answers:
masya89 [10]2 years ago
7 0

Answer:

total toffees=12

remaining toffees=12-(4+3)

=12-7

=5

fraction of toffees left

= 5/12

Vinvika [58]2 years ago
4 0

Answer:

5/12

Step-by-step explanation:

3 + 5 = 7

12/12 - 7/12 = 5/12

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shen baked b cookies. his family ate 11 of them. using b, write an expression for the number of cookies that remained.
Jobisdone [24]

Step-by-step explanation:

So, lets write out the equation you have right now.

B - 11 = ?

You can have B be whatever you want. It must be higher than 11 (unless your teacher or whoever your guardian is allows negative numbers). In this case, I will use 15.

B = 15

15 - 11 = ?

Solve the equation and you get 4. Simple!

7 0
3 years ago
Rewrite the equation below so that it does not have fractions.
Andreas93 [3]

Answer:

20x=-27 standard form or

20x+27=0 for implicit form

Step-by-step explanation:

5 0
2 years ago
Can someone solve this addition of rational expressions question
jarptica [38.1K]

3/b - 8 + 7/b +3

combine like terms

3/b + 7/b -8+3

10 /b -5

4 0
3 years ago
Solve for x: 10 = x + 25<br><br> A. -15<br> B. 35<br> C. 15<br> D. -35
julsineya [31]

Answer:

X = -15

Step-by-step explanation:

Switch Sides

X + 25 = 10

Subtract 25 From Both Sides

X + 25 - 25 = 10 - 25

Simplify

X = -15

Best Of Luck,

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3 0
3 years ago
When the Stanford‐Binet IQ test came into use in 1932, it was adjusted so that scores for each age group of children followed ro
Andrei [34K]

Answer:

2.28% of children had very superior scores in 1932.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 15

IQ scores above 130 are often called "very superior." What percentage of children had very superior scores in 1932?

This is 1 subtracted by the pvalue of Z when X = 130. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{130 - 100}{15}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of children had very superior scores in 1932.

7 0
3 years ago
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