-4r>16 I have to solve this for my math hw
1 answer:
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Answer:
Third option: x=0 and x=16
Step-by-step explanation:
Isolating √(2x+4): Addind √x both sides of the equation:
Squaring both sides of the equation:
Simplifying on the left side, and applying on the right side the formula:
Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:
Squaring both sides of the equation:
This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:
Factoring: Common factor x:
x (x-16)=0
Two solutions:
1) x=0
2) x-16=0
Solving for x: Adding 16 both sides of the equation:
x-16+16=0+16
x=16
Let's prove the solutions in the orignal equation:
1) x=0:
x=0 is a solution
2) x=16
x=16 is a solution
Then the solutions are x=0 and x=16
Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)=
(Derivation)
f´(x0)=
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)=
f´(x0)=
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =