Let distance form the pole = x and height of the hill = y ft
now we can set up 2 equayions
tan 18 = (40-y)/x
tan 14 = y/x
from second equation y = sxtan14 so we have:-
tan 18 = ( 40 - x tan 14) / x
x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40
x = 40 / (tan18 + tan 14) = 69.66 feet Answer
This question is soooo easy
Step-by-step explanation:
(3x)^2+(5)^2+2.3x.5
9x^2+25+30x
Answer:
Step-by-step explanation:
X = 1/2 arc QS
arc QS is
360 =145+105+QS
110 = QS
so X is 1/2 QS
X= 55°
To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
<span>(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c</span>² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
