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grandymaker [24]
3 years ago
12

Lillian is deciding between two parking garages. Garage A charges an initial fee of $4 to park plus $3 per hour. Garage B charge

s an initial fee of $9 to park plus $2 per hour. Let AA represent the amount Garage A would charge if Lillian parks for tt hours, and let BB represent the amount Garage B would charge if Lillian parks for tt hours. Write an equation for each situation, in terms of t,t, and determine the hours parked, t,t, that would make the cost of each garage the same.
Mathematics
1 answer:
Georgia [21]3 years ago
4 0

Answer:

5 hours

Step-by-step explanation:

Lillian is deciding between two parking garages.

Let the time required to park be represented by t

A = Amount

From Garage A

A = the amount Garage A would charge if Lillian parks for t hours

B = the amount Garage B would charge if Lillian parks for t hours.

Garage A

Garage A charges an initial fee of $4 to park plus $3 per hour.

A = $4 + $3 × t

A = 4 + 3t

Garage B charges an initial fee of $9 to park plus $2 per hour.

B = $9 + $2 × t

B = 9 + 2t

The hours parked, t, that would make the cost of each garage the same is calculated by equating A to B

A = B

4 + 3t = 9 + 2t

Collect like terms

3t - 2t = 9 - 4

t = 5 hours

Therefore, the hours parked, t, that would make the cost of each garage the same is 5 hours

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Answer:

300 seconds

Step-by-step explanation:

First, you have to know how much half a minute is. Half a minute is 30 seconds.

Second, you multiply 30 by 10 because he answered 10 questions.

30 * 10 = 300

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7 0
3 years ago
18. Determine the common difference, the fifth term, and the sum of the first 100 terms of the following sequence:
Ksenya-84 [330]

a_1=1,\ a_2=2.5,\ a_3=4,\ a_4=5.5,\ ...\\\\a_2-a_1=2.5-1=1.5\\a_3-a_2=4-2.5=1.5\\a_4-a_3=5.5-4=1.5\\a_{n+1}-a_n=1.5=constans\\\\\text{It's an arithmetic sequence with}\\a_1=1,\ \boxed{d=1.5}\\\\a_n=a_1+(n-1)d\to a_n=1+(n-1)(1.5)=1+1.5n-1.5\\\\a_n=1.5n-0.5\\\\a_5=1.5(5)-0.5=7.5-0.5=7\\\boxed{a_5=7}\\\\\text{The formula of a Sum of the First n Terms of an Arithmetric Sequence:}\\\\S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n\\\\\text{We have:}\\a_1=1,\ d=1.5,\ n=100\\\\\text{Substitute}

S_{100}=\dfrac{(2)(1)+(100-1)(1.5)}{2}\cdot100=\dfrac{2+(99)(1.5)}{1}\cdot50\\\\=(2+148.5)\cdot50=150.5\cdot50=7,525\\\\\boxed{S_{100}=7,525}\\\\Answer:\\the\ common\ difference:\ d=1.5\\the\ fifth\ term:\ a_5=7\\the\ sum\ of\ first\ 100\ terms:\ S_{100}=7,525

8 0
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anyanavicka [17]
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if there is one negative then it will be negative, so in this case it will be -7 / 2= 

answer= -3 1/2
8 0
3 years ago
I forgot how to do this. Can anyone help me please
Svetach [21]

Answer:

34

Step-by-step explanation:

180 since it is supplementary

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7 0
2 years ago
Read 2 more answers
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Scilla [17]

Answer:

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Step-by-step explanation:

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