Expand and simplify 2(p + 2q

X-3=10 does anyone know this

vovikov84 [41]

Answer:

Are you trying to solve for x?

x= 13

just kick the 3 to the other side, so a negative 3 would become a positive 3:

x= 10 + 3

x= 13

You can also use cymath it gives you the answer and explanation.

Hope this helps.

5 0

3 years ago

I’m confused :( I will mark as Brainliest and give you points

Ludmilka [50]

Answer:

123.5 square inches

Step-by-step explanation:

Given: To find the area of a rectangle, you have to multiply base times height.

To find the area of a triangle, you have to do base times height devided by 2.

Finding the area: Let's break up this shape into polygons. At the bottom there is a rectangle. We know that to find the area of the rectangle you have to do base times height. 13in•7in will give you 91in square for the rectangle.

Now for the triangle. If you can see, if you break the triangle in half, there are 2 right triangles. Let's look at the right one for now. Since we know that to find the area of a triangle you have to do base times height divided by 2, you do 5in•6.5in=32.5in. 32.5in divided by 2 is 16.25in square which is the area of one triangle. You might be wondering why i did 5•6.5, and that's because at the bottom of the rectangle you can see it's 13in, and 13in÷2=6.5in.

We already found the area of the rectangle and one triangle. The other triangle is equal to it so we can just do 16.25+16.25=32.5in square for both of the triangles.

Now we add it all up: 32.5+91=123.5 square inches

8 0

3 years ago

√(6+x-x²)=9 I have to put this just to submit it.

Sergio [31]

We know that it must equal 9, and that we do x•x-x+6 and find the square root

4 0

3 years ago

Type SSS, SAS, ASA, SAA, or HL to describe these triangles.

GalinKa [24]

Answer:

HL

Step-by-step explanation:

3 0

3 years ago

Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6

Oksi-84 [34.3K]

Answer:

$-1/3$

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

$9x^2-15x$

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

$9x^2-15x=6$

Subtract 6 from both sides:

$9x^2-15x-6=0$

Divide everything by 3:

$3x^2-5x-2=0$

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

$3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0$

Find the x using the Zero Product Property:

$3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2$

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

$x=-1/3$

Assume that the correct symbol is >. Thus,

$x>-1/3$

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

$9x^2-15x$

0 is indeed less than six, so our first correct solution is:

$x>-1/3$

For the second one, do the same thing. We have:

$x=2$

Assume that the correct symbol is <. Thus:

$x$

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

$9x^2-15x$

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

$x>-1/3 \text{ and } x$

Together, we can write them as:

$-1/3$

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

6 0

3 years ago

Expand and simplify 2(p + 2q – 3).