Answer:
is the sum 78 or 7,878 (i.e. was there a stutter)?
In any event, this sum must be even, so 3 consecutive even integers would be n, n+2 & n+4 whose sum is 3n + 6.
Set that to either 78 or 7878, whichever is intended, & solve for n. If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.
No stress! Just logic! Keep the faith!
Step-by-step explanation:
Answer:
50%
Step-by-step explanation:
Given that one side of the pancake is burned. The pancake you were served cannot be the one that is not burned on either side. Therefore, you were either served the pancake burned on both sides, or the pancake that was only burned in one side. Thus, there is a 50% percent chance that the other side is also burned.
The answer to this equation is C.
C. (x + 7)2<span> – 47</span>
Answer:
<h3>
The second: f(-5) = 2</h3>
Step-by-step explanation:
x = -5
-5 < -4 and if x<-4 then f(x) = - 2x - 8
so:
f(-5) = - 2(-5) - 8 = 10 - 8 = 2
Answer:
The P-value is 0.0166.
Step-by-step explanation:
<u>The complete question is:</u> In a one-tail hypothesis test where you reject H0 only in the lower tail, what is the p-value if ZSTAT = -2.13.
We are given that the z-statistics value is -2.13 and we have to find the p-value.
Now, the p-value of the test statistics is given by the following condition;
P-value = P(Z < -2.13) = 1 - P(Z
2.13)
= 1 - 0.9834 = <u>0.0166</u>
Assuming that the level of significance is 0.10 or 10%.
The decision rule for rejecting the null hypothesis based on p-value is given by;
- If the P-value of the test statistics is less than the level of significance, then we have sufficient evidence to reject the null hypothesis.
- If the P-value of the test statistics is more than the level of significance, then we have insufficient evidence to reject the null hypothesis.
Here, the P-value is more than the level of significance as 0.0166 > 0.10, so we have insufficient evidence to reject the null hypothesis, so we fail to reject the null hypothesis.