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Jlenok [28]
3 years ago
5

Find the numerical value of one trigonometric function of x if sinxcotx=1/3

Mathematics
1 answer:
san4es73 [151]3 years ago
4 0

\bf sin(x)cot(x)=\cfrac{1}{3}\implies ~~\begin{matrix} sin(x) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \cfrac{cos(x)}{~~\begin{matrix} sin(x) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=\cfrac{1}{3}\implies cos(x) = \cfrac{1}{3} \\\\\\ x = cos^{-1}\left( \cfrac{1}{3} \right)\implies x \approx 70.53^o

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Which is a conditional statement for the sentence?
vova2212 [387]

The conditional proposition for the given sentence is:

"For all real numbers a, b, and c, if a = b, then a−c=b−c."

<h3>Which one is a conditional statement?</h3>

A conditional statement is of the form:

If P, then Q.

Where P and Q are two propositions.

The sentence is:

"For all real numbers a, b, and c, a = b implies that a−c=b−c."

So the propositions are:

P = "a = b"

Q = " a - c = b - c"

Where we need to define that this works for all real numbers.

So the conditional proposition is:

"For all real numbers a, b, and c, if a = b, then a−c=b−c."

So the correct option is C.

If you want to learn more about conditional propositions:

brainly.com/question/11073037

#SPJ1

6 0
2 years ago
Given (8x+3k)(9x−2)=0, the product of all solutions is (−3). Find k.
denis-greek [22]

Answer:

k=36

Step-by-step explanation:

Given\ (8x+3k)(9x-2)=0\\\\Product\ of\ two\ expressions\ is\ zero\ then\ one\ of\ them\ must\ be\ zero.\\\\If\ (9x-2)=0\\\\Add\ 2\ both\ the\ sides\\\\9x-2+2=0+2\\\\9x=2\\\\divide\ both\ sides\ by\ 9.\\\\\frac{9x}{9}=\frac{2}{9}\\\\x=\frac{2}{9}\\\\When\ (8x+3k)=0\\\\8x=-3k\\\\x=\frac{-3k}{8}\\\\

Solutions\ are\ \frac{2}{9}\ and\ \frac{-3k}{8}\\\\Product\ of\ these\ solutions=-3\\\\\frac{2}{9}\times \frac{-3k}{8}=-3\\\\-\frac{6k}{72}=-3\\\\\frac{2k}{72}=1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ divide\ both\ sides\ by\ -3\\\\k=\frac{72}{2}=36

Other Method:

Product of solutions: Product of the roots of the polynomial ax^2+bx+c=0 is given by \frac{c}{a}

(8x+3k)(9x-2)=0\\\\(72x^2+27kx-16x-6k)=0\\\\72x^2+(27k-16)x-6k=0\\\\Here\ a=72,\ b=(27k-16),\ c=-6k\\\\\frac{c}{a}=\frac{-6k}{72}\\\\Product\ is\ given=-3\\\\-\frac{6k}{72}=-3\\\\6k=72\times 3\\\\k=\frac{72\times 3}{6}\\\\k=36

4 0
3 years ago
Work this out by giving your answer as a fraction 2/3 - 1/2
suter [353]

When subtracting fractions, you need to make sure the denominators are the same. In 2/3 - 1/2, the denominators are different. To make them the same, find the least common denominator. In this case, the common denominator is 6

2/3 becomes 4/6

1/2 becomes 3/6

Now subtract the fractions with the common denominator

4/6 - 3/6 = 1/6

The answer is 1/6

Hope this helps. Please mark me as Brainliest. Thanks!

7 0
2 years ago
Read 2 more answers
Write a linear function ff with f(0)=2f(0)=2 and f(2)=4
drek231 [11]
When x is o, f(0)=2, when x is 2, f(2)=4, so you are given two points, (0,2) and (2,4)
find the slope: m=(4-2)/(2-0)=1
write it in point-slope form, using either point: (y-2)=1(x-0)
so the equation is y=x+2

4 0
4 years ago
Use this picture and help please
Svetlanka [38]
65 degrees because then it adds to 180 degrees
6 0
3 years ago
Read 2 more answers
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