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lana [24]
2 years ago
12

Please help me I need help as soon as possible

Mathematics
1 answer:
kotykmax [81]2 years ago
8 0
You can find the perimeter by just counting the distance of every line segment all around the shape since they have vertical and horizontal slopes.
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NEED HELP FAST‼️‼️
ch4aika [34]

Answer:

Step-by-step explanation:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as

Applying this rule to the three given points will mean....

Point A = (-2, 3) becomes A ' = (-2, -3)

Point B = (0, 3) becomes B ' = (0, -3)

Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

4 0
3 years ago
Tomas factored the polynomial completely. What is true about his final product? 3x4−18x3+9x2−54x Ax(x2+B)(x+C)
iren2701 [21]

Answer:

A and B are both 3.  

Step-by-step explanation:

The given polynomial is 3x^4-18x^3+9x^2-54x.

We factor the GCF to obtain:

3x(x^3-6x^2+3x-18)

We factor further by grouping to get:

3x[x^2(x-6)+3(x-6)]

3x(x^2+3)(x-6)

We compare this to the given factored expression:

3x(x^2+3)(x-6)=Ax(x^2+B)(x+C)

We must have A=3,B=3, C=-6

8 0
3 years ago
Read 2 more answers
If the 50th and 51st terms of an arithmetic sequence are 140 and 142, find the 1st term
morpeh [17]

Answer:

The first term is 42.

Step-by-step explanation:

The common difference is 142  - 140 = 2 so we have

50th term = a1 + 2(50 -1) = 140    where a1 is the first term

a1 + 98 = 140

a1 = 140 - 98 =  42.

4 0
3 years ago
Two airliners are 1600 miles apart and heading toward each other at different altitudes. The first plane is traveling north at 6
viktelen [127]
In approximately around 2 hours and 10 mins
4 0
3 years ago
The half-life of cobalt-60 (used in
Likurg_2 [28]

Answer:

6.25 gm left

Step-by-step explanation:

Find the number of half lives in 26.3 years

   26.3 / 5.26 = 5 half lives

(1/2)  ^5   = 1/32 nd  of the original will be left

   1/32 * 200g = 6.25 gm left

5 0
2 years ago
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