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3 years ago

(1) x + 4 > 8. If you need to solve for x, what's the first step?

Mathematics

2 answers:

Serggg [28]3 years ago

7 0

B is the correct answer

emmasim [6.3K]3 years ago

5 0

Answer:

Step-by-step explanation:

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Study time (hours)

xxTIMURxx [149]

Answer: A B and C

Step-by-step explanation:

I did the usatestprep

7 0

3 years ago

In a standard deck of 52 cards, what is the probability of drawing one card and getting a face card or a heart?

serious [3.7K]

Answer: I hope this helps :)

Step-by-step explanation:

All in all, this leaves us with #(Heart or Face card) = 13+12–3=22 cards.

So your probability would be p(Heart or Face card)= 22/52 or 11/26 or 42,3%

(but they are all the same)

4 0

3 years ago

Read 2 more answers

What is the mean of 4,6,8,20, 12?

Delvig [45]

Answer:

add them all up which is 40 then divide by the amount of numbers there are. in this case 5, so 40 ÷ 5 = 8

6 0

3 years ago

Read 2 more answers

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

I’m kinda stuck on this

stepan [7]

Answer: 4.08and 3 repeating

Step-by-step explanation: you do top x top and bottom x bottom and divide the 2

6 0

3 years ago