Answer
First we add all of the students that take either algebra 1, algebra 2 or both: 14+20+7= 41 which means out of 60 students 41 take either algebra 1, algebra 2 or both to find the rest of the students we subtract 41 from 6060-41= 19 answer: 19 students don't take either subject
Answer: used quizz it helps me
Step-by-step explanation: trust
Assuming we are solving for t
2<-1t
3
Answer:
not sure man... goodluck tho
Answer:
x = 7
Step-by-step explanation:
![2log_5(x-3)-log_58= log_52\\\\2log_5(x-3) =log_52+log_58\\\\2log_5(x-3) =log_5(2\times 8) \\\\2log_5(x-3) =log_516\\\\2log_5(x-3) =log_54^2 \\\\2log_5(x-3) =2 log_54 \\\\log_5(x-3) =log_54 \\\\x - 3 = 4\\\\x = 4+3\\\\\huge \orange { \boxed{x = 7}}](https://tex.z-dn.net/?f=2log_5%28x-3%29-log_58%3D%20log_52%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E2log_5%28x-3%29%20%3Dlog_52%2Blog_58%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E2log_5%28x-3%29%20%3Dlog_5%282%5Ctimes%208%29%20%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E2log_5%28x-3%29%20%3Dlog_516%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E2log_5%28x-3%29%20%3Dlog_54%5E2%20%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E2log_5%28x-3%29%20%3D2%20log_54%20%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3Elog_5%28x-3%29%20%3Dlog_54%20%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3Ex%20-%203%20%3D%204%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3Ex%20%3D%204%2B3%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%5Chuge%20%5Corange%20%7B%20%5Cboxed%7Bx%20%3D%207%7D%7D%3C%2Fp%3E%3Cp%3E)