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cluponka [151]
3 years ago
7

There are 65 people coming to your party and each person will need one cup. How many packages of cups should you buy if one pack

age contains 3 cups?
ANWSER:





STEP BY STEP EXAMPLE:​
Mathematics
2 answers:
melomori [17]3 years ago
8 0

Answer: 22

Step-by-step explanation: 65 divided by 3 is 22

Tema [17]3 years ago
6 0

Answer:

21or22

Step-by-step explanation:

65/3

You might be interested in
Please help me!!!! So confused
yarga [219]

<em>Question:</em>

The area of the kite is 48 cm². What are the lengths of the diagonals PR and QS?

________


<em>Solution:</em>

You can split the kite into two isosceles triangles:   PSR and PQR.

Assume that both diagonals intersect each other at the point O.


•   Area of the triangle PSR:

           m(PR) · m(OS)
A₁  =  ————————
                     2

           (x + x) · x
A₁  =  ——————
                  2


           2x · x
A₁  =  ————
              2


A₁ = x²        (i)


•   Area of the triangle PQR:

            m(PR) · m(PQ)
A₂  =  ————————
                     2

           (x + x) · 2x
A₂  =  ——————
                  2

           2x · 2x
A₂  =  ————
               2

           4x²
A₂  =  ———
             2


A₂ = 2x²        (ii)


So the total area of the kite is

A = A₁ + A₂ = 48


Then,

x² + 2x² = 48

3x² = 48

            48
x²  =  ———
            3

x² = 16

x = √16

x = 4 cm


•   Length of the diagonal PR:

m(PR) = x + x

m(PR) = 2x

m(PR) = 2 · 4

m(PR) = 8 cm


<span>•   </span>Length of the diagonal SQ:

m(SQ) = x + 2x

m(SQ) = 3x

m(SQ) = 3 · 4

m(SQ) = 12 cm


I hope this helps. =)


Tags:  <em>polygon area triangle plane geometry</em>

8 0
3 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
Make t the subject of the formula <br> P= 3-2t<br> —————<br> 4+t
Rufina [12.5K]

Answer:

t = \frac{3 - 4p}{p + 2}

Step-by-step explanation:

Given

P = \frac{3 - 2t}{4 + t}

Required

Make t the subject

P = \frac{3 - 2t}{4 + t}

Cross Multiply

P * (4 + t) = 3 - 2t

4p + tp = 3 - 2t

Collect Like Terms

tp + 2t = 3 - 4p

Factorize:

t(p+2) = 3 - 4p

Make t the subject

t = \frac{3 - 4p}{p + 2}

5 0
3 years ago
Somebody once told me the world is gonna roll me
nikdorinn [45]

Answer:

same

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Making high-stakes insurance decisions. The Journal of Economic Psychology (Sept. 2008) published the results of a high-stakes e
Andrej [43]

Answer:

a. P(24)=0.00007

b. P(23)=0.00018

c. There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

Step-by-step explanation:

The probabilities of two events ("fire"and "theft") are compared to the probabilities of a certain number of days of rain during July.

The probabilities of "fire"and "theft" are around P=0.0001, and we need to calculate if the probability of exactly 23 and exactly 24 days of rain July have approximately the same probability.

Rain frequencies for the months of July and August were shown to follow a Poisson distribution with a mean of 10 days per month.

The parameter then is:

\lambda=10

The probability of k days of rain is:

P(k)=\frac{10^ke^{-10}}{k!}

For 24 days, the probability is:

P(24)=\frac{10^{24}e^{-10}}{24!}=\frac{1*10^{24}*4.54*10^{-5}}{6.20*10^{23}}  = 0.00007

The probability of 23 days of rain is 27% less than P=0.0001.

For 23 days of rain, the probability is:

P(23)=\frac{10^{23}e^{-10}}{23!}=\frac{1*10^{23}*4.54*10^{-5}}{2.59*10^{23}}  = 0.00018

The probability of 23 days of rain is 76% more than P=0.0001.

There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

8 0
3 years ago
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