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3 years ago

Four Fifths of 2/3 would be what number?

Mathematics

1 answer:

alina1380 [7]3 years ago

7 0

Answer:

(4/5)

Step-by-step explanation:

Two-thirds of the number is (2/3)x. 10 more than two-thirds of the number is (2/3)x +10. Hence the given problem will be (4/5)x =(2/3)x +10.

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2 years ago

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3 years ago

Plant B is 6 2/3 inches tall. and C is 4 4/15 inches tall. Complete the sentences and show your reasoning

artcher [175]

Answer:

Plant C is 0.64 times as tall as Plant B

Plant C is 2.4 inches shorter than Plant B

Step-by-step explanation:

Plant B is 6 2/3 inches tall. Plant B is 20/3 inches tall.

Plant C 4 4/15 inches tall. Plant C is 64/15 inches tall.

a.) Plant C is shorter than Plant B $= \frac{64}{15} \times \frac{1}{\frac{20}{3} } = \frac{64}{15} \times\frac{3}{20} = \frac{16}{25}$ = 0.64 times.

b.) Plant C is shorter than Plant B by = $\frac{20}{3} - \frac{64}{15} = \frac{100}{15} - \frac{64}{15} = \frac{100 -64}{15} = \frac{36}{15} = 2\frac{2}{5} = 2.4$ inches

3 0

3 years ago

Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t

alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

6 + 6 = 12 seeds, which means that $N = 12$

6 treated, which means that $k = 6$

Five sprouted, which means that $n = 5$

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076$

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0

3 years ago