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xenn [34]
3 years ago
13

Solve the equation. 6x−7=2x+13

Mathematics
2 answers:
Sergio [31]3 years ago
8 0

Answer:

6x - 7 = 2x + 13

6x - 2x = 13 + 7

4x = 20

x = 20/4

x = 5

Hope it helps!

BigorU [14]3 years ago
6 0
X=5 that’s the answer
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A function is given. h(t) = t2 + 3t; t = −1, t = 2
Arlecino [84]

Answer:

(a) The net change of the function is 12.

(b) The average rate of change of the function 4.

Step-by-step explanation:

The average rate of change of function f(x) over the interval a\leq x\leq b is given by this expression:

average rate of change =  \frac{net \:change \:in \:y}{change \:in \:x} = \frac{f(b)-f(a)}{b-a}

It is a measure of how much the function changed per unit, on average, over that interval.

Given:

h(t)=t^2+3t\\\\t=-1\\t=2

(a) To find the net change of the function, first we calculate the values of h(2) and h(-1)

h(-1)=(-1)^2+3(-1)=-2\\\\h(2)=(2)^2+3(2)=10

The net change is simply the difference

h(2)-h(-1)=10-(-2)=12

(b) The average rate of change takes the net change and divides it by the change in the t value.

\frac{12}{2-(-1)} =\frac{12}{3}=4

5 0
3 years ago
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No Spam. I will mark Brainliest, if you get it right. A tank's length is 4 feet longer than its width. The height is 2 feet more
dmitriy555 [2]

Answer: 3

Step-by-step explanation:

Let say x the width of the tank,

x+4 its length,

x+2 its height

Volume=105=x(x+4)(x+2)\\\\P(x)=x^3+6x^2+8x-105=0\\\\105=3*5*7\\\\P(1)\neq 0\\P(-1)\neq 0\\P(3)=0\\\\\begin{array}{|c|cccc|}&x^3&x^2&x&1\\&1&6&8&-105\\x=3&&3&27&105\\----&--&--&--&--\\&1&9&35&0\\\end{array}\\\\\\P(x)=x^3+6x^2+8x-105=(x-3)(x^2+9x+35)\\And \ x^2+9x+35\ is\ not \ factorizable\ (\Delat=9^2-4*35 < 0)\\

<u>width=3</u>

length=3+4=7

height=3+2=5

4 0
3 years ago
The bases of a cylinder have a diameter of 4 inches. The height of the cylinder is 6 inches. What is the total surface area of t
Nostrana [21]

Answer:

Step-by-step explanation:

area of base = π4² = 16π in²

lateral area = 2πrh = 2π·4·6 = 48π in²

surface area = 2×16π + 48π = 80π in² ≅ 251.3 in²

3 0
2 years ago
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blagie [28]

Answer:

I cannot really see the q

4 0
3 years ago
A rectangle has a perimeter of 14 inches. A similar rectangle has a perimeter of 10 inches. If the length of the larger rectangl
Jet001 [13]

Answer:

2.9 in.

Step-by-step explanation:

Let x in be the width of the larger rectangle.  If the length of the larger rectangle is 4 inches and the perimeter of the larger rectangle is 14 in, then

x+4+x+4=14,\\ \\2x=14-8,\\ \\2x=6,\\ \\x=3\ in.

If two rectangles are similar, then their lengths and widths are proportional with the scale factor k. Thus, the length of the smaller rectangle is 4k in and the width of the smaller rectangle is 3k in. If the perimeter of the smaller rectangle is 10 in, then

4k+3k+4k+3k=10,\\ \\14k=10,\\ \\k=\dfrac{10}{14}=\dfrac{5}{7},\\ \\4k=\dfrac{20}{7}\approx 2.9\ in,\\ \\3k=\dfrac{15}{7}\approx 2.1\ in.

7 0
3 years ago
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