The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3
The line is passing through the point = (-6,-3)
The slope of the line = 0
The point slope form is

Substitute the values in the equation
(y-(-3)) = 0×(x-(-6))
We have to convert this equation the slope intercept form
Slope intercept form is
y = mx + b
Where m is the slope of the line
b is the y intercept
(y-(-3)) = 0×(x-(-6))
y+3 = 0×(x+6)
y+3 = 0
y = -3
Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.
Learn more about slope intercept form here
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Answer:
if you are lookng for C it is 17
Step-by-step explanation:
we are given
absolute value of 2 and 2 3rd and negative 9 over 4
Firstly , we need write it in terms of expression
2 and 2 3rd is

so, we get as

now, we can simplify it
Firstly , we will find common denominator


we can see that
all denominators are same
so, we can combine numerators


..............Answer
Answer:

Step-by-step explanation:
Given that:

for 
That means, angle
is in the 3rd quadrant.
To find:
Value of cot(t)
Solution:
First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.
In 3rd quadrant, tangent and cotangent are positive.
All other trigonometric ratios are negative.
Let us have a look at the following identity:

here, 
So, 

But, angle
is in 3rd quadrant, so value of

Answer:
2nd one is corect
60% is 93.49$ but u are getting 100$ discount so 2nd is ans