Answer:
If in a day, 458 call options are picked by these traders, around <u> 246.2 </u>of them will be winners, give or take<u> 10.67 </u>.
Step-by-step explanation:
Hello!
Your study variable is X: the number of winning calls in a sample of 458 calls.
The variable has a binomial distribution since you have two possible outcomes, that the call is a winning call (success) or that the call is not a winning call (failure), each call is independent and the probability of success is p= 0.5375 and the probability of failure q= 1-p= 1-0.5375= 0.4625.
The expected value for a binomial distribution is
E(X)= n*p= 458 * 0.5375= 246.175
And to know the standard error (or standard deviation) you have to calculate the square root of the variance:
V(X)= n*p*q= 458*0.5375*0.4625= 113.85
√V(X)= √113.85= 10.67
I hope it helps!
-35 and 42/100........................................
Answer:
I'm sorry if i'm wrong but I hope this helps
Step-by-step explanation:
Volume = l³ = 500
![length = \sqrt[3]{500} = 7.937m](https://tex.z-dn.net/?f=length%20%3D%20%20%5Csqrt%5B3%5D%7B500%7D%20%20%3D%207.937m)
The question is incomplete. The complete question is :
Justin drinks 1 litter of water during the soccer practice. He drank 2,000 milliliters of water at his game. How many liters of water did he drink during his game and his practice? Explain.
Solution :
It is given that :
During practice, Justine drank = 1 liter of water
During game, Justine drank = 2000 milliliters of water
We know that,
1 liter = 1000 mL
Therefore, during the game, Justine drank :
1000 mL = 1 liter
∴ 2000 mL = 2 liter
So Justine drank 2 liters of water during his soccer game and 1 liter of water during his practice.
To find the median, add up the frequency column to find how many trains there were in total. There were 44 trains in total in this grouped frequency table, so work out 44 + 1 2 = 45 2 = 22.5. The median is therefore between the 22nd and 23rd values.
