I need the equation to be able to help
A difference of 840 degrees
800 - (-40) = 840
When removing a negative number from a positive number you get a positive
- + - = +
800 - (-40)
^ ^
Negatives (2)
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Answer:
x = -3±i sqrt(2)
Step-by-step explanation:
x^2+6x + 11 =0
Subtract 11 from each side
x^2+6x + 11-11 =0-11
x^2+6x =-11
Take the coefficient of the x terms
6
Divide by 2
6/2 =3
Square it
3^2 =9
Add it to each side
x^2+6x + 9 =-11+9
x^2 + 6x+9 = -2
The left hand side becomes (x+ (6/2) )^2
(x+3)^2 = -2
Take the square root of each side
sqrt((x+3)^2) = ±sqrt(-2)
x+3 = ±sqrt(-2)
x+3= ±i sqrt(2)
Subtract 3 from each side
x+3-3 = -3±i sqrt(2)
x = -3±i sqrt(2)
