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Ostrovityanka [42]
3 years ago
5

Which statements verify that the solution set to |x + 3| < 5 is –8 < x < 2? Check all that apply.

Mathematics
2 answers:
Harman [31]3 years ago
8 0

Answer:

1 and 4

Step-by-step explanation:

Only true statements out of the option

Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

1 and 4

Step-by-step explanation:

You might be interested in
Find the measure of AC
max2010maxim [7]

Answer:

7 inch

Step-by-step explanation:

AC= BC+AB

= (BD-CD) + radius of B

= (radius of B-radius of D) + 4.5

=(4.5-2) +4.5

=2.5+ 4.5

=7 inch

I hope this is correct.

5 0
3 years ago
In the united states, voters who are neither democrat nor republican are called independent. it is believed that 12% of voters a
Nitella [24]

Answer:

a) 0.0245 = 2.45%

b) 0.9483 = 94.83%

c) 0.6931 = 69.31%

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are independent, or they are not. The probability of a person being independent is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

It is believed that 12% of voters are independent.

This means that p = 0.12

Survey of 29 people

This means that n = 29

a. what is the probability that none of the people are independent? probability =

This is P(X = 0). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{29,0}.(0.12)^{0}.(0.88)^{29} = 0.0245

0.0245 = 2.45% probability that none of the people are independent

b. what is the probability that fewer than 7 are independent? probability =

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{29,0}.(0.12)^{0}.(0.88)^{29} = 0.0245

P(X = 1) = C_{29,1}.(0.12)^{1}.(0.88)^{28} = 0.0971

P(X = 2) = C_{29,2}.(0.12)^{2}.(0.88)^{27} = 0.1853

P(X = 3) = C_{29,3}.(0.12)^{3}.(0.88)^{26} = 0.2274

P(X = 4) = C_{29,4}.(0.12)^{4}.(0.88)^{25} = 0.2016

P(X = 5) = C_{29,5}.(0.12)^{5}.(0.88)^{24} = 0.1374

P(X = 6) = C_{29,6}.(0.12)^{6}.(0.88)^{23} = 0.0750

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0245 + 0.0971 + 0.1853 + 0.2274 + 0.2016 + 0.1374 + 0.0750 = 0.9483

0.9483 = 94.83% probability that fewer than 7 are independent

c. what is the probability that more than 2 people are independent? probability =

Either two or less are, or at least 3 are independent. The sum of the probabilities of these events is decimal 1. So

P(X \leq 2) + P(X > 2) = 1

We want P(X > 2). So

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{29,0}.(0.12)^{0}.(0.88)^{29} = 0.0245

P(X = 1) = C_{29,1}.(0.12)^{1}.(0.88)^{28} = 0.0971

P(X = 2) = C_{29,2}.(0.12)^{2}.(0.88)^{27} = 0.1853

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0245 + 0.0971 + 0.1853 = 0.3069

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.3069 = 0.6931

0.6931 = 69.31% probability that more than 2 people are independent

3 0
3 years ago
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Answer: X=5/2, Y= 15, T=4
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3 years ago
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AleksandrR [38]

Answer:

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3 0
3 years ago
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iren2701 [21]
Y = 1x + -3
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4 years ago
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