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svlad2 [7]
3 years ago
14

What is 1519 rounded to the first digit

Mathematics
1 answer:
sweet [91]3 years ago
7 0

Answer:

1520

Step-by-step explanation:

hope it is helpful

You might be interested in
Given the points A(3, 4) and B (6, 10), find the
Dvinal [7]

Answer:

P (5 , 8)

Step-by-step explanation:

P (x,y) partition A (x₁ , y₁) B (x₂ , y₂) into ratio AM:MB = a:b = 2:1  ... a=2 , b=1

x = (bx₁ + ax₂) / (a+b)

  = (1 * 3 + 2 * 6) / (2 + 1)

  = 15/3

  = 5

y = (by₁ + ay₂) / (a+b)

  = (1 * 4 + 2 * 10) / (2 + 1)

  = 24/3

  = 8

P (5 , 8)

8 0
3 years ago
What is 3.2 × 10−4 m/h in centimeters per second? A. 8.889 × 10−6 cm/s B. 8.889 × 10−5 cm/s C. 1.152 × 10−5 cm/s D. 1.152 × 10−7
atroni [7]
3.2 x 10^{-4} x  \frac{100}{3600} = 8.888 x  10^{-6}

therefore ur answer is OPTION A 8.889 x 10-6 cm/s
4 0
3 years ago
Please help.<br><br> Best answer will get brainliest.
nikdorinn [45]

Answer:

59.1 for the mean

Step-by-step explanation:

You add all the numbers together and divde it by the amount of numbers there are.

7 0
3 years ago
Read 2 more answers
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
/d/e/1FAIpQLSclFkZlgkRij_Rf2abUD8YgyQtKMgZR65VhFeEjQ96N34Edog/formResponse
Pavel [41]

Answer:

Assuming you mean on a number line.

5 0
3 years ago
Read 2 more answers
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