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a_sh-v [17]
3 years ago
6

15 points!!

Mathematics
1 answer:
saw5 [17]3 years ago
5 0

Answer:

If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.

Step-by-step explanation:

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Rewrite each number using scientific
ki77a [65]

Answer:

300- 3e2

106,000 = 1.06e5

0.0000397= 3.97e-5

4,356,000= 4.356e6

0.0157= 1.57e-2

Step-by-step explanation:

3 0
3 years ago
Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 22 Pennies 27 Dimes 9 Nickels
kap26 [50]

Answer:

P(Penny\ and\ Dime) = \frac{9}{116}

Step-by-step explanation:

Given

Pennies = 22

Dimes = 27

Nickels = 9

Quarters = 30

Required

P(Penny\ and\ Dime)

This is calculated as:

P(Penny\ and\ Dime) = P(Penny) * P(Dime)

Since it is a selection without replacement, the computation is:

P(Penny\ and\ Dime) = \frac{Penny}{Total} * \frac{Dime}{Total-1}

So, we have:

P(Penny\ and\ Dime) = \frac{22}{22+27+9+30} * \frac{Dime}{22+27+9+30-1}

P(Penny\ and\ Dime) = \frac{22}{88} * \frac{27}{87}

P(Penny\ and\ Dime) = \frac{1}{4} * \frac{9}{29}

P(Penny\ and\ Dime) = \frac{9}{116}

5 0
2 years ago
HELPPPP
Tamiku [17]

Answer:

D) -9/4

Step-by-step explanation:

-4(3)³/3(4)²

-4(27)/3(16)

-108/48

divides both by 12

- 9/4

7 0
3 years ago
Read 2 more answers
The amount of polonium-210 remaining, p(t), after t days in a sample can be modeled by the exponential function p(t) = 100e−0.00
Archy [21]

Answer:

% Po lost = 100[1 - e^(-0.005t)]  %; 73.0 g

Step-by-step explanation:

p(t) = 100e^(-0.005t)

Initial amount:        p(0) = 100

Amount remaining: p(t) = 100e^(-0.005t)

Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]

% of Po lost  = amount lost/initial amount × 100 %

= [1 - e^(-0.005t)]  × 100 % = 100[1 - e^(-0.005t)]  %

p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g

The mass of polonium remaining after 63 days is 73 g.

4 0
3 years ago
In the July 2007 issue, Consumer Reports examined the calorie content of two kinds of hot dogs: meat (usually a mixture of pork,
kifflom [539]

Answer:

Since we FAIL to reject the null hypothesis, then if we construct an interval of 95% of confidence, the 0 should be included, because on the test hypothesis we conclude that there would be no significant difference between the means of the two groups analyzed, and the results obtained on the hypothesis test needs to be consistent with the confidence interval.

Step-by-step explanation:

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

\bar x_{meat}=111.7 represent the sample mean of calories for the meat hot dogs

\bar x_{beef}=135.4 represent the sample mean of calories for the beef hot dogs

The system of hypothesis on this case would be:

Null hypothesis: \mu_{meat}-\mu_{beef}=0

Alternative hypothesis: \mu_{meat}-\mu_{beef}\neq 0

On this case we have the p value obtained, after calculate the statistic and we got that p_v =0.124 if we select a 5% significance level \alpha=0.05 we see that p_v >\alpha and on this case we can FAIL to rejec the null hypothesis, so there is not a significant difference between the mean of the two tpes of hot dogs analyzed at 5% of significance.

And since we FAIL to reject the null hypothesis, then if we construct an interval of 95% of confidence, the 0 should be included, because on the test hypothesis we conclude that there would be no significant difference between the means of the two groups analyzed, and the results obtained on the hypothesis test needs to be consistent with the confidence interval.

8 0
3 years ago
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