All categories

3 years ago

Solve the inequality. 42 < –6d

Mathematics

1 answer:

____ [38]3 years ago

4 0

Divide both sides by -6 and don't forget to flip the inequality symbol
-7>d
d<-7

You might be interested in

Write the sum of the numbers as the product of their gcf and another sum 32 and 20

pav-90 [236]

Ymm makes no sense but its pulsing so yea the answer is 52

7 0

3 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

3 years ago

5/2 c = 8 1/3 please help me

Diano4ka-milaya [45]

9514 1404 393

Answer:

3 1/3

Step-by-step explanation:

Multiply both sides by the reciprocal of the coefficient of c.

(5/2c)(2/5) = (8 1/3)(2/5)

c = (25/3)(2/5) = 50/(3·5) = 10/3

c = 10/3 = 3 1/3

3 0

3 years ago

Read 2 more answers

Simplify each expression

Hatshy [7]

Answer:

$5. \: \: 8 + 5(7) = 8 + 35 = 43$

I hope I helped you^_^

3 0

3 years ago

A parabola has a minimum value of 0, a y-intercept of 4, and an axis of symmetry at x = -2

sveta [45]

Since the minimum value is 0 and axis of symmetry is -2 this means that the vertex is at -2,0 now with the y intercept of 4. You can now plug the values into Vertex form which will be y=a(x-h)^2+k. a being the shrink or stretch of the parabola, h being the x value of the vertex, and k being the y value of the vertex. with all of that plugged in it should look like y=(x+2)^2. You can check this equation by plugging in 0 as x which should find the y intercept of 4. So it should then look like y=(0+2)^2 -> y=(2)^2 -> y=4

3 0

3 years ago