Answer:
- The equation that represent the cost C of renting a car and driving x miles is C = $39.11 + $0.50x
- $130 can travel 181.32 miles
Step-by-step explanation:
From the question, a rental company rents a luxury car at a daily rate of 39.34 $ plus $.50 per mile, that is
$0.50 is added to the initial $39.34 for every mile.
The equation that represent the cost C of renting a car and driving x miles is
C = $39.34 + $0.50x
Now, to determine how many miles 130$ can travel,
we will put C = $100, and determine x in the above equation
$130 = $39.34 + $0.50x
$130 - $39.34 = $0.50x
$90.66 = $0.50x
x = $90.66/$0.50
x = 181.32
Hence, $130 can travel 181.32 miles
The distance between is 5
An=Asub1(r)n-¹
=5(-2)7-¹
=5(64)
A7=320
Since we have to solve the given formula for h(height) so, the correct option is (a)
Answer:
x1 = 2
x2 = -1/3
Step-by-step explanation:
3x^2-5x-2=0
D=25-4*(-2)*3 = 25 + 24 = 49 --> sqrt 49 = 7
x1 = 5 + 7 / 2*3 = 2
x2 = 5 - 7 / 2*3 = -1/3
