V(t) = 2t^2 - 3t - 3
for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3
at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2
Answer:
Step-by-step explanation:
5,9,11,(13,16),16,19,21
the mean(middle number) = (13 + 16) / 2 = 29/2 = 14.5
Q1 = (9 + 11) / 2 = 20/2 = 10
Q3 = (16 + 19) / 2 = 35/2 = 17.5
interquartile range (IQR) = Q3 - Q1 = 17.5 - 10 = 7.5 <==
Answer: B. 4
Step-by-step explanation:
First, I did the equation out.
Second, I simply it all the way through.
Third, to get 4
When is cos (x) = 0? <em>at 90° (aka π/2)</em>
Answer: 
A) -3√288=-3√(144*2)=-3√144<span>√2=-3*12</span><span>√2=-36</span><span>√2
b) </span>5√320=5<span>√(64*5)=</span>5<span>√64</span><span>√5=5*8</span><span>√5=40</span><span>√5</span>
