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svet-max [94.6K]
3 years ago
8

I need to find the value of x and the measure of the exterior angle

Mathematics
1 answer:
adell [148]3 years ago
7 0

Given:

In a right angle triangle, the measure of exterior angle is (9x+16)^\circ.

The measure of opposite interior angle is (5x-14)^\circ.

To find:

The value of x.

Solution:

Exterior angle theorem: In a triangle the measure of an exterior angle is equal to the measure of sum of two interior angles.

Using exterior angle theorem, we get

(9x+16)^\circ=90^\circ+(5x-14)^\circ

(9x+16)^\circ=(5x+76)^\circ

9x+16=5x+76

Isolate the variable x.

9x-5x=-16+76

4x=60

x=\dfrac{60}{4}

x=15

The value of x is 15. So, the measure of the exterior angle is:

(9x+16)^\circ=(9(15)+16)^\circ

(9x+16)^\circ=(135+16)^\circ

(9x+16)^\circ=151^\circ

Therefore, the value of x is 15 and the measure of the exterior angle is 151 degrees.

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Find x, if 3x − 5(y + x ) ^2 = 16 and 4x + 2(y + x )^ 2 = 30
lana66690 [7]

Answer:

x = 7

Step-by-step explanation:

Start by solving for (y+x)^2 which is a common expression for both equations. Then in the first equation:

3\,x5\,(y+x)^2=16\\3x-16=5\,(y+x)^2\\(y+x)^2=\frac{3\,x-16}{5}

and in the second equation:

4\,x+2\,(y+x)^2=30\\2\,(y+x)^2=30-4\,x\\(y+x)^2=15-2\,x

Now we make the two (y+x)^2 expressions equal so we get:

\frac{3\,x-16}{5} =15-2\,x\\3\,x-16=75-10\,x\\13\,x=75+16\\13\,x=91\\x=7

8 0
3 years ago
I need help with this one and someone help me
Mekhanik [1.2K]
The value of angle Y is -120° because you know that angle S is half of angle Y and -60*2 equals -120°. Hope that helps!
6 0
3 years ago
(6-3(cube root of 6)/(cube root of 9)
MatroZZZ [7]

For this case we must simplify the following expression:

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}

Multiplying the numerator and denominator by(\sqrt [3] {9}) ^ 2

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =

We rewrite:

\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =

By properties of powers we have that:

a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =

We rewrite, moving the exponent within the radical:

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =

We can rewrite3 * 3 ^ 3 = 81

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =

We simplify:

\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =

We apply distributive property:

\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =

Simplifying we finally have:

2 \sqrt [3] {3} - \sqrt [3] {18}

Answer:

2 \sqrt [3] {3} - \sqrt [3] {18}

5 0
3 years ago
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