The range would be [-3, infinity)
-3 (inclusive) to infinity (non-inclusive)
The equation is f(x) = 4x^2 - 4.
You can find this by using an equation with parenthesis that equal each of the zeros.
f(x) = (x - 1)(x + 1)
Now, this equation will not give us the vertex that we're looking for. So, we must add a constant being multiplied to the front of it.
f(x) = c(x - 1)(x + 1)
Now we can find the constant by putting our vertex into the equation and solving.
f(x) = c(x - 1)(x + 1)
-4 = c(0 - 1)(0 + 1)
-4 = c(-1)(1)
-4 = -1c
c = 4
Now we put the c into the original equation and solve for standard form.
f(x) = 4(x - 1)(x + 1)
f(x) = 4(x^2 - 1)
f(x) = 4x^2 - 4
Answer:
that equation isn't factorable
Answer:
Step-by-step explanation:
D is your answer
$56.18
Answer:
4x - 6
Step-by-step explanation:
2 × 2x = 4x
2 × -3 = -6
4x -6