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uysha [10]
3 years ago
12

An agricultural company is trying to decide which type of fertilizer to use on its crops. The company concerned with the average

yield on its crops as well as the variance of their yields. In a sample of 41 different fields with using fertilizer A, the average crop yield per acre is 185 tons with a standard deviation of 35 tons. In a separate sample of 61 different fields using fertilizer B, the average crop yield is 175 tons with a standard deviation of 28 tons. When testing the hypothesis that there is no difference between the average yields using the different fertilizers, if the test statistic is 1.53 and the critical value is 2.57 then what is your conclusion concerning the null hypothesis?
Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0

Answer:

We do not reject the null

Step-by-step explanation:

Given that :

Sample size, n = 41

Test statistic ; Zstatistic ;= 1.53

Critical value ; Zcritical ; = 2.57

The null hypothesis H0 ;

H0: μ1 - μ2 = 0

Alternative hypothesis, H1 ;

H1: μ1 ≠ μ2

Decision region :

Reject Null ; if |Zstatistic ≥ Zcritical|

Zstatistic > Zcritical

Result :

1.53 < 2.57

Zstatistic < Zcritical

Hence, we do not reject the null ; there is no significant evidence that there is difference in the average yield of the two samples.

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Point B has coordinates ​(​1,2​). The​ x-coordinate of point A is -8. The distance between point A and point B is 15 units. What
Xelga [282]

Answer:

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}} (1)

Where:

l_{AB} - Length of the line segment AB.

x_{A}, x_{B} - x-coordinates of points A and B.

y_{A}, y_{B} - y-coordinates of points A and B.

If we know that l_{AB} = 15, x_{A} = -8, x_{B} = 1 and y_{B} = 2, then the possible coordinates of point A is:

\sqrt{(1+8)^{2}+(2-y_{A})^{2}} = 15

81 + (2-y_{A})^{2} = 225

(2-y_{A})^{2} = 144

2-y_{A} = \pm 12

There are two possible solutions:

1) 2-y_{A} = -12

y_{A} = 14

2) 2 - y_{A} = 12

y_{A} = -10

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

8 0
3 years ago
What is the value of p? (p 2)−4=14
Over [174]
P+2-4=14
p-2=14
add 2
p+2-2=14+2
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8 0
3 years ago
What is -3(y+2)^2-5+6y in standard from
satela [25.4K]

Answer:

Step-by-step explanation:

-3(y²+4y+4)-5+6y

=-3y²-12 y-12-5+6 y

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Given (1, -3) and (5, 1). The slope of the line is The equation of the line is
guapka [62]

To find the slope of the line we can use the following formula:

\frac{y.2 - y.1}{x.2 - x.1} = m

1 - (-3)/5 - 1

4 / 4

1

<h3>The slope of the line is equal to 1.</h3>

To find the equation, we can just use slope-intercept form.

We already know the slope, so our current equation is y = x

By knowing the slope, we can apply the slope to our lowest pair of coordinates to find the y value when x = 0.

Subtract 1 from the x and y values of (1, -3)

(0, -4) is our new point, and so we know the y-intercept is -4.

<h3>Our equation for the line is y = x - 4</h3>
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jeka57 [31]

Answer:

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Step-by-step explanation:

Write and solve an equation involving this information, using x as the distance traveled, in miles:

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Next, divide both sides by $0.25/mile:

        $3.25

x = ------------------ = 13 miles

      $0.25/mile

The length of the taxi ride was 13 miles.

7 0
3 years ago
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