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MakcuM [25]
2 years ago
5

Find the zeros of the function; To the nearest Hundredth. PLEASE HELP

Mathematics
1 answer:
Vitek1552 [10]2 years ago
3 0

Answer:

The zeros are ( -7.17,0) and (-4.291,0)

Step-by-step explanation:

I put it into desemos

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Solve the system of linear equations by substitution.<br><br> 8x−13y=0<br> 12x+3=y
Oliga [24]

Answer:

x = - 39/148

y = -6/37

Step-by-step explanation:

substitute the given value of y into the equation to get 8x-13 (12x+3)=0

solve for x to get x= - 39/148

substitute the given value of x into 12x+3=y

12 x (-39/148) + 3 = y

-6/37 = y

7 0
2 years ago
Twice the difference of a number and 9 equals 5.
emmasim [6.3K]

Answer:

7

Step-by-step explanation:

if the number is x then you know 2x-9=5

2x=14

x=7

so the number is 7

8 0
3 years ago
-2 1/6 + -3 1/3 + -5 1/2
N76 [4]

Answer:

-2 1/6 + -3 1/3 + -5 1/2 = -11

Step-by-step explanation:

-2 + -3 + -5 = -10

-1/6 +- 1/3 + -1/2 = -1

-10+-1=-11

3 0
3 years ago
Answer correct for brainliest and also get a thanks ! :-) please help !!
GREYUIT [131]

 

Y =2x +14

-4x –y = 4 so y = -4x – 4


2x + 14 = -4x – 4

2x + 4x = -4 - 14

6x = -18

x = -18/6

x = -3

Y =2x +14

y = 2(-3) +14

y= -6 +14

y=8


answer:

y-coordinate is 8

3 0
3 years ago
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
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