For 5-9, use the diagram below to classify each of the angles.

If the angle ZYX measures 45 degrees ,then arc XY measures 45 degrees. TRUE OR FALSE ?!

Angelina_Jolie [31]

The picture in the attached figure

the correct question is
<span>If the angle ZYX measures 45 degrees, then arc XZ measures 45 degrees. TRUE OR FALSE ?!

we know that
if </span>angle ZYX measures 45 degrees
then
arc XZ=angle ZYX---------> by central angle

therefore
arc XZ=45°

the answer is
TRUE

6 0

3 years ago

The relationship between a distance x in a garden and the corresponding distance y in a model of the garden is y = kx. A triangu

iragen [17]

Answer:

1/6

Step-by-step explanation:

4 0

3 years ago

The 3rd term of (a-b)4 is

fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

3rd term = C(4, 2) * a^2b^2

Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

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4 0

1 year ago

The pyramid shown has a height of 14 inches and a base area of 60 in2. Find the volume of the pyramid.

Kamila [148]

Volume of pyramid is $280 in^{3}$ .

The pyramid has a height 14 inches and a base area of 60 in2.

What is volume?

Volume is a three - dimensional quantity that is used to measure the capacity of a solid shape.

Volume of the pyramid = $Area base$ X $\frac{height}{3}$

= $60.\frac{14}{3}$

= $280$ $in^{3}$

So the volume of pyramid = $280$ $in^{3}$

Learn more about the Volume visit:

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8 0

2 years ago

Six identical squares are cut from the corners and edges of an 80 cm by 50 cm cardboard rectangle. the remaining piece is folded

Anna11 [10]

Check the picture.

let the length of a side of each of the squares removed be x.

The box formed will have dimensions: 80-2x, 50-2x, x(the height)

So the volume can be expressed as a function of x as follows:

f(x)=(80-2x)(50-2x)x= $[4000-160x-100x+4 x^{2} ]x=(4 x^{2}-260x+4000)x$

so $f(x)=4 x^{3}-260x^{2}+4000x$

the solutions of f'(x)=0 gives the inflection points, so the candidates for maxima points,

$f'(x)=12x^{2}-520 x +4000=0$

solving the quadratic equation, either by a calculator, graphing software, or by other algebraic methods as the discriminant formula, we find the solutions

x=10 and x=33.333

plug in f(x) these values to see which greater:

$f(10)=(80-20)(50-20)10=60*30*10=18000$ cm cubed

$f(33.333)=(80-66.666)(50-66.666)33.333=$ which is negative because (50-66.666)<0

Answer: 18000 cm cubed

5 0

3 years ago

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