Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
1,79,07,120 ways
Step-by-step explanation:
Ways in which 3 solids can be chosen from 19 solids = 19 c 3
33 striped prints can be chosen from 99 striped prints in 9 c 3 ways
33 floral prints can be chosen from 121 floral prints in 12 c 33 ways
So, total ways = (19 c 3) (9 c 3) (12 c 3)
(969) (84) (220)
1,79,07,120
ADD = 300
ITI = 323
ON - 33 (Almost a 6 at the end!)
Y intercept = 7/-2 or -3.5
Connect the dots to each other
