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SVETLANKA909090 [29]

2 years ago

12

At the craft store, Martina bought a bag of yellow and orange marbles. She received 15 marbles in all. 6 of the marbles were yel

low. What percentage of the marbles were yellow?
Write your answer using a percent sign (%).

1 answer:

vampirchik [111]2 years ago

8 0

Answer:

40%

Step-by-step explanation:

6/15=2/5=4/10=40%

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A student’s first step to solving the equation 5(x – 2) = 10 was to simplify it to 5x – 2 = 10. Did the student make a mistake?

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Read 2 more answers

2. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, o

Brut [27]

Hello!

To solve algebraic equations, we need to use SADMEP. SADMEP is an acronym used only solve for x in algebraic equations. SADMEP is expanded to be: subtraction, addition, division, multiplication, exponents, and parentheses.

(a) 4 + 2(-1) = 10 + 2 (multiply)

4 + -2 = 10 + 2 (add)

2 = 12

This equation has no solutions because <u>2 is never equal to 12</u>.

(b) 30 = 10 - (6 + 10) (simplify the parentheses)

30 = 10 + -1(16) (multiply)

30 = 10 - 16 (simplify)

30 = -6

This equation has no solutions because<u> 30 and -6 is never equal to each other</u>.

(c) 8x = 4x + 4x + 10(x - x)

8x = 4x + 4x + 10(x - x) (simplify [add and subtract])

8x = 8x + 10(0) (multiply)

8x = 8x

This equation has an infinite number of solutions because if you <u>substitute any value into the original equation</u>, <u>both sides of the equation</u> will be <u>always equal</u>.

7 0

3 years ago

Oksana_A [137]

Answer:

c) A rectangle with width of 9 mm and length of 45 cm.

d) A rectangle with width of 10 cm and length of 44 cm.

Step-by-step explanation:

Given:

Length of the rectangle = 32 in.

Width of the rectangle = 8 in.

First we will find the ratio of length by width.

$\frac{length}{width}= \frac{32}{8} = \frac{4}{1} \ \ \ \ equation \ 1$

Now we need to find from the given Option which rectangles are not similar to Carl's Rectangle.

So we will check for each.

a) A rectangle with width of 23 cm and length of 92 cm.

we will find the ratio of length by width.

$\frac{length}{width}= \frac{92}{23} = \frac{4}{1} \ \ \ \ equation \ 2$

By Definition of Similar rectangles which states that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $=$ equation 2

Hence This rectangle is similar to Carl's rectangle.

b) A rectangle with width of 2.5 inch and length of 10 inch.

we will find the ratio of length by width.

$\frac{length}{width}= \frac{10}{2.5} = \frac{4}{1} \ \ \ \ equation \ 2$

By Definition of Similar rectangles which states that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $=$ equation 2

Hence This rectangle is similar to Carl's rectangle.

c) A rectangle with width of 9 mm and length of 45 cm.

we will find the ratio of length by width.

$\frac{length}{width}= \frac{45}{9} = \frac{5}{1} \ \ \ \ equation \ 2$

By Definition of Similar rectangles which states that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $\neq$ equation 2

Hence This rectangle is not similar to Carl's rectangle.

d) A rectangle with width of 10 cm and length of 44 cm.

we will find the ratio of length by width.

$\frac{length}{width}= \frac{44}{10} = \frac{11}{5} \ \ \ \ equation \ 2$

By Definition of Similar rectangles which states that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $\neq$ equation 2

Hence This rectangle is not similar to Carl's rectangle.

6 0

3 years ago