Answer:
Given 7b²-21b-273=7, the solutions are x1 = 8 and x2 = -5.
Step-by-step explanation:
Given 7b²-21b-273=7, first you need to equal zero. So
7b²-21b-273-7=0 ⇒ 7b²-21b-280 = 0
The secon step is to find the solutions applying Bhaskara´s formula x = (-b ± √(b²-4×a×c))/2×a
Where a=7, b= -21 and c= -280
After you identified each term, you have to replace it on the formula so....
x = (21 ± √(21² - 4×7×(-280)))/2×7 ⇒ x = (21 ± √(441 + 7840))/14 ⇒ x = (21 ± √8281)/14
Then you will obtain two values for x, called x1 = 8 and x2=-5.
A, line segment : part of a line that is bounded by two distinct end points, and contains every point of the line between it's endpoints.
Answer:
I'll text you so I can help you for sure
Answer:
1.) x=4
2.) x=14
Step-by-step explanation:
FOR #1:
1.) In order to solve the parallelogram, you must know that each opposite sides must equal...
so KL=JM and KJ=LM
2.) To solve for "x", you must substitute

so it should end up with...

3.) Solve the equation with some algebra

FOR #2:
1.) In order for a square, rectangle, parallelogram, (or any shape with four sides), it must equal to 360°. And you just have two given angles, which equal to 180, so that means the unknown equals to 180...So in this case you should have

as your equation...
2.) Solve with algebra


<u><em>multiplied</em></u>