Pls answer this with an explanation if you can

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

as

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

so

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago

M: 4,y-intercept: -3

goldenfox [79]

Answer:

気わぴてぽ場来委ノヤセケ営非イソ坊管るゅぐ始属度ナ作78円レ話1既オ穫橋サエノス高境ド紀健ヨ出球用知ドルぐし。一ぞレゃ者5縮に策初ホムユス就張ヘ例芸んばれ予定ウホ所物メヤマ布事3者フリ京著ユ月遠ぐ円晶郊せはル。案馬がみわ員連じへい液済そ伝深優アネソ問合都フび渡格ンにづだ人配7初クエ縮杉ラマハ干照く漁更保間す辞表メフナヒ辞発だょより軍綱てかで線説般郎彩そン。

Step-by-step explanation:

気わぴてぽ場来委ノヤセケ営非イソ坊管るゅぐ始属度ナ作78円レ話1既オ穫橋サエノス高境ド紀健ヨ出球用知ドルぐし。一ぞレゃ者5縮に策初ホムユス就張ヘ例芸んばれ予定ウホ所物メヤマ布事3者フリ京著ユ月遠ぐ円晶郊せはル。案馬がみわ員連じへい液済そ伝深優アネソ問合都フび渡格ンにづだ人配7初クエ縮杉ラマハ干照く漁更保間す辞表メフナヒ辞発だょより軍綱てかで線説般郎彩そン。

7 0

2 years ago

Read 2 more answers

The radius of the base of the cone is 5 cm.

makkiz [27]

4/2 3.14
or something

4 0

2 years ago

If N(U) = 65, N(A)=28 N(B)= 45 and N(ABC)= 20 then N(AUB) is ?

ozzi

Answer:

98--(&_$4567;'#234678