The point (2, 5) is not on the curve; probably you meant to say (2, -5)?
Consider an arbitrary point Q on the curve to the right of P, 
, where 
. The slope of the secant line through P and Q is given by the difference quotient,
where we are allowed to simplify because 
.
Then the equation of the secant line is
Taking the limit as 
, we have
so the slope of the line tangent to the curve at P as slope 2.
- - -
We can verify this with differentiation. Taking the derivative, we get
and at 
, we get a slope of 
, as expected.
Given b=21 and ∠β=60°,
a = 12.12436 = 7√3
j = 24.24871 = 14√3
∠α = 30° = 0.5236 rad = π/6
h = 10.5
area = 127.30573 = 147√3/2
perimeter = 57.37307
inradius = 4.43782
circumradius = 12.12436 = 7√3
Answer is
j = 24.24871 = 14√3
Answer:3!
Step-by-step explanation:
Your answer would be 24 zeros. The 24 above the 10 represents how many zeros will be in the standard notation form.
Answer:the answer is 1/10
Step-by-step explanation:
