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3 years ago

What factor does the width of the peak of a normal curve depend on?

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

8 0

The width of a peak depends on A. Standard deviation

Tanzania [10]3 years ago

4 0

Answer:

Option A-Standard deviation is the correct option.

Step-by-step explanation:

The width of the peak of a normal curve depend on Standard deviation.

Rest all options have bell shaped curves that are smooth and curvy and does not possess peaks.

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Mari is adding (-7) and (-2). She adds their absolute values and says the answer is 9.

Helen [10]

Answer:

ari is adding (-7) and (-2). She adds their absolute values and says the answer is 9.

What did Mari forget?

that is neither positive nor negative

to move left on the number line

to keep the sign of the larger integer

to keep the sign of the two integers being adde

Step-by-step explanation:

5 0

3 years ago

What is the missing constant term in the perfect square that starts with x2+18xx^2+18xx2+18xx, squared, plus, 18, x ?

katrin2010 [14]

Answer:

Step-by-step explanation:

Given the expression: $x^2+18x$

To make it a perfect square, we follow the following steps.

Divide the coefficient of x by 2

Coefficient of x=18, 18/2=9

Square It

9 X 9=81

Add it to the expression

$x^2+18x+81$

This is written as a perfect square as: $(x+9)^2$

The constant term required therefore is 81.

4 0

3 years ago

Read 2 more answers

The length of a rectangle is twice as long as the width of the rectangle.

Rashid [163]

Answer: length = 8cm

Width = 4cm

Step-by-step explanation:

Let the width of the rectangle be represented by x.

Since the length of a rectangle is twice as long as the width of the rectangle, then the length will be: = 2 × x = 2x

Note that, Area of a rectangle = Length × Width

Therefore,

2x × x = 32

2x² = 32

Divide both side by 2

2x²/2 = 32/2

x² = 16

x = ✓16

x = 4

Therefore, width = 4cm

Since length = 2x

Length = 2 × 4cm = 8cm

Check: length × width = Area

8cm × 4cm = 32cm²

8 0

3 years ago

Use the box plots comparing the number of boy dogs and number of girl dogs attending doggy daycare each day for a month to answe

satela [25.4K]

The boxplots 1 and 2 represent the distribution of data using a five number summary for the male and the female attendance

The first box plot represents the male's boxplot.

So, we have:

Upper quartile (Q3) = 14
Lower quartile (Q1) = 2

The IQR is the difference between the above values

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2 = 12

So: the IQR for the males' data is 12

<h3>(b) The difference in the median values</h3>

From the first and second boxplots, we have:

Median male = 10
Median female = 18

The difference (d) between these values is

d = 18 - 10

d = 8

So: the difference between the median values of each data set is 8

<h3>(c) The distribution of data</h3>

This is dependent on whether the dataset has an outlier or not.

From the figure, we have:

Male's data: presence of an outlier - use median
Female's data: absence of an outlier - use mean

So: the male dataset is measured by median, while the mean is a better measure of center for the female's data

<h3>(d) Reason for outliers</h3>

A possible reason for outliers is sampling problems