I believe the answers are
1) D
2) B
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The volume of air in a person's lungs is about 615 ml, at a pressure of 760 mm Hg. Inhalation occurs when the pressure in the lungs drops to 752 mm Hg. To what volume do the lungs expand?
Answer:
621.5mL
Explanation:
Given parameters:
Initial volume = 615mL
Initial pressure = 760mmHg
Final pressure = 752mmHg
Unknown;
Final volume = ?
Solution:
To solve this problem, we simply apply Boyle's law.
"the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁V₁ = P₂V₂
P and V are the pressure
1 and 2 are the initial and final states
Now insert the parameters and start;
760 x 615 = 752 x V₂
V₂ = 621.5mL
<u>Answer:</u> The new pressure will be 101.46 kPa.
<u>Explanation:</u>
To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.
The equation given by this law is:
where,
are initial pressure and temperature.
are final pressure and temperature.
We are given:
By using conversion factor: 
Putting values in above equation, we get:
Hence, the new pressure will be 101.46 kPa.
