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matrenka [14]
3 years ago
9

How do I work out 60% of 25?

Mathematics
2 answers:
Elza [17]3 years ago
7 0
25 x (60/100) = 15
25 - 15 = 10
ira [324]3 years ago
3 0

Answer:

15

Step-by-step explanation:

Multiply: 25x.60=15

The reason why you multiply 25 times .60 is because you need to change the percentage to a decimal. The way you change you from a percentage to a decimal is by moving the decimal twice to the left.

So, 60%=.60

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Simplify the expression.
Alja [10]

Answer:

-2r^3+4r^2+12r-4

Step-by-step explanation:

6r^3-2r^2+12r-4-8r^3+6r^2

(6r^3-8r^3)+(-2r^2+6r^2)+12r-4

simplify

-2r^3+4r^3+12r-4

4 0
4 years ago
Is birth a qualitative or quantitative?<br><br> Birth year
7nadin3 [17]

Answer:

f we are talking about months of births its qualitative, if numbers such as 11, 10, 5, representing days or months or years is involved as data then it is quantitative.

Step-by-step explanation:

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3 years ago
Solve for v. -8 +5v=-33​
Dima020 [189]

Answer:

v = -5

Step-by-step explanation:

Step 1: Write out equation

-8 + 5v = -33

Step 2: Add 8 on both sides

-8 + 8 + 5v = -33 + 8

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3 0
3 years ago
Read 2 more answers
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mixer [17]
Answer:

C


Step-by-Step explanation:
6 0
3 years ago
In a large section of a statistics​ class, the points for the final exam are normally​ distributed, with a mean of 71 and a stan
kumpel [21]

Answer:

The lowest score on the final exam that would qualify a student for an​ A is 80.

The lowest score on the final exam that would qualify a student for a B is 74.68.

The lowest score on the final exam that would qualify a student for a C is 67.33.

The lowest score on the final exam that would qualify a student for a​ D is 62.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71 and a standard deviation of 7.

This means that \mu = 71, \sigma = 7

Grades are assigned such that the top​ 10% receive​ A's, the next​ 20% received​ B's, the middle​ 40% receive​ C's, the next​ 20% receive​ D's, and the bottom​ 10% receive​ F's.

This means that:

90th percentile and above: A

70th percentile and below 90th: B

30th percentile to the 70th percentile: C

10th percentile to the 30th: D

Lowest score for an A:

Top 10% receive A, which means that the lowest score that would qualify a student for an A is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9, so X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 71}{7}

X - 71 = 7*1.28

X = 80

The lowest score on the final exam that would qualify a student for an​ A is 80.

Lowest score for a B:

70th percentile, which is X when Z has a pvalue of 0.7, so X when Z = 0.525.

Z = \frac{X - \mu}{\sigma}

0.525 = \frac{X - 71}{7}

X - 71 = 7*0.525

X = 74.68

The lowest score on the final exam that would qualify a student for a B is 74.68.

Lowest score for a C:

30th percentile, which is X when Z has a pvalue of 0.3, so X when Z = -0.525.

Z = \frac{X - \mu}{\sigma}

-0.525 = \frac{X - 71}{7}

X - 71 = 7*(-0.525)

X = 67.33

The lowest score on the final exam that would qualify a student for a C is 67.33.

Lowest score for a D:

10th percentile, which is X when Z has a pvalue of 0.1, so X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 71}{7}

X - 71 = 7*(-1.28)

X = 62

The lowest score on the final exam that would qualify a student for a​ D is 62.

4 0
3 years ago
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