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4 years ago

Question 4 (2 points)

Computers and Technology

2 answers:

rodikova [14]4 years ago

6 0

Answer:

Add the broadcast jump! code to the end of Scratch Cat's code.

Explanation:

If we broadcast the jump! code, then the Gobo will listen, and he will start jumping up and down. It looks like that he is not getting what Scratch Cat is saying, and if the message of Scratch Cat is broadcasted then Gobo will listen to what Scratch Cat is telling. Hence, the above option is the correct option.

Murljashka [212]4 years ago

5 0

Answer:

Add the broadcast jump code to the end of scratch cat's code.

Explanation:

That block sends a message and Gobo recives it.

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Where should you look for most objective and unbaised information

jekas [21]

Google, would be the best because of all of the different site, hope this helps!
: )

8 0

3 years ago

write a program that keeps names and email addresses in a dictionary as key-value pairs. the program should display a menu that

erma4kov [3.2K]

To write a program that keeps names and email addresses in a dictionary as key-value pairs check the code given below.

<h3>What is key-value pairs?</h3>

In a key-value pair, two related data elements are combined: a value, which is a variable that belongs to the set (for example, male/female, green, 100), and a key, which is a constant that defines the data set (for example, gender, color, price).

A key-value pair could look something like this when fully formed:

gender = male

color = green

price > 100

↓↓↓//<u>Python code</u>//↓↓↓

import pickle

import sys

try:

f=open('email.dat','rb')

d=pickle.load(f)

f.close()

except:

d={}

while True:

print('\n1. Find a email address')

print('2. Add name and email address')

print('3. Change an email address')

print('4. Delete an email address')

print('5. Exit\n')

choice=input('\nEnter a choice: ')

if choice:

choice=int(choice)

else:

print('\nEnter a number')

continue

if choice == 1:

while True:

name=input('\nEnter the name ')

if name:

if name in d:

print('\n%s is the email id of %s \n' % (d[name],name))

break

else:

print('\n Email not found \n')

break

else:

print('\nName cannot be empty\n')

continue

elif choice==2:

while True:

name=input('\nEnter the name ')

if name:

break;

else:

print('\nName cannot be empty \n')

continue

while True:

email=input('\nEnter the email address ')

if email:

d[name]=email

break

else:

print('\nEmail cannot be empty\n')

continue

elif choice==3:

while True:

name=input('\nEnter the name to change the email address ')

if name:

if name in d:

email=input('\nEnter the new email address ')

d[name]=email

print('\nEmail address changed \n')

break;

else:

print('\nName not found \n')

break

else:

print('\nName cannot be empty \n')

continue

elif choice == 4:

while True:

name=input('\nEnter the name to remove ')

if name:

if name in d:

del d[name]

print('\nName and Email address removed \n ')

break;

else:

print('\nName not found \n')

break

else:

print('\nName cannot be empty\n')

continue

elif choice == 5:

f=open('email.dat','wb')

pickle.dump(d,f)

f.close()

sys.exit()

else:

print('\nEnter a valid choice ')

Learn more about key-value pair

brainly.com/question/29414672

#SPJ1

3 0

1 year ago

Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r

kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

INVOKE Str_find,ADDR target, ADDR source

mov position,eax

jz wasfound ; ZF=1 indicates string found

mov edx,OFFSET str3 ; string not found

call WriteString

jmp quit

wasfound: ; display message

mov edx,OFFSET str1

call WriteString

mov eax,position ; write position value

call WriteDec

mov edx,OFFSET str2

call WriteString

quit:

exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

; to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

INVOKE Str_length,pTarget ; get length of target

mov lenTarget,eax

INVOKE Str_length,pSource ; get length of source

mov lenSource,eax

mov edi,OFFSET target ; point to target

mov esi,OFFSET source ; point to source

; Compute place in target to stop search

mov eax,edi ; stop = (offset target)

add eax,lenTarget ; + (length of target)

sub eax,lenSource ; - (length of source)

inc eax ; + 1

mov stop,eax ; save the stopping position

; Compare source string to current target

cld

mov ecx,lenSource ; length of source string

L1:

pushad

repe cmpsb ; compare all bytes

popad

je found ; if found, exit now

inc edi ; move to next target position

cmp edi,stop ; has EDI reached stop position?

jae notfound ; yes: exit

jmp L1 ; not: continue loop

notfound: ; string not found

or eax,1 ; ZF=0 indicates failure

jmp done

found: ; string found

mov eax,edi ; compute position in target of find

sub eax,pTarget

cmp eax,eax ; ZF=1 indicates success

done:

ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0

3 years ago

The data in RAM is saved when the computer is turned off. True or False

IgorLugansk [536]

Answer:

False

Explanation:

This is False because when the computer shuts off completely all the data in the ram is deleted

4 0

4 years ago

Based on the chart below, which pie flavors make up approximately one-half of the total? A pie chart shows the following pie fla

Vladimir [108]

Based on the data, a combination of strawberry rhubarb (12%), chocolate mud pie (23%) and cherry (14%) would amount to 49% which is close to half of the pie chart or 50%. Another probable answer is the combination of coconut (9%), banana cream (10%), pumpkin (11%), and other (21%) which is equal to 51%.

8 0

3 years ago

Read 2 more answers