All categories

2 years ago

Edhesive 8.5 code Practice help me pls

Computers and Technology

1 answer:

Hoochie [10]2 years ago

3 0

Answer:

twainQuotes = ['I have never let my schooling interfere with my education.', 'Get your facts first, and then you can distort them as much as you please.', "If you tell the truth, you don't have to remember anything.", 'The secret of getting ahead is getting started.', "Age is an issue of mind over matter. If you don't mind, it doesn't matter. "]

print(twainQuotes)

twainQuotes.sort()

print(twainQuotes)

twainQuotes.insert(1,'Courage is resistance to fear, mastery of fear, not absence of fear.' )

print(twainQuotes)

Explanation:

You might be interested in

Two strategies for keeping your files in sync

zlopas [31]

Answer:

1. MS Cloud

2. G Drive

Explanation:

5 0

2 years ago

Select the steps for adding artwork into a placeholder on a presentation slide

Sloan [31]

Answer:

Open the presentation that you want to add a slide to.

In the pane that contains the Outline and Slides tabs, click Slides, and then click where you want to add a slide.

Explanation:

6 0

3 years ago

Half of the integers stored in the array data are positive, and half are negative. Determine the

jonny [76]

Answer:

Check the explanation

Explanation:

Below is the approx assembly code for above `for loop` :-

1). mov ecx, 0

2). loop_start :

3). cmp ecx, ARRAY_LENGTH

4). jge loop_end

5). mv temp_a, array[ecx]

6). cmp temp_a, 0

7). branch on nge

8). mv array[ecx], temp_a*2

9). add ecx, 1

10). jmp loop_start

11). loop_end :

Assumptions :-

*ARRAY_LENGTH is register with value 1000000

*temp_a is a register

Frequency of statements :-

1) will be executed one time

3) will be executed 1000000 times

4) will be executed 1000000 times

5) will be executed 1000000 times

6) will be executed 1000000 times

7) `nge` will be executed 1000000 times, branch will be executed 500000 times

8) will be executed 500000 times

9) will be executed 1000000 times

10) will be executed 1000000 times

Cost of statements :-

1) 10 ns

3) 10ns + 10ns + 10ns [for two register accesses and one cmp]

4) 10ns [for jge ]

5) 10ns + 100ns + 10ns [10ns for register access `ecx`, 100ns for memory access `array[ecx]`, 10ns for mv]

6) 10ns + 10ns [10ns for register_access `temp_a`, 10ns for mv]

7) 10ns for nge, 10ns for branch

8) 30ns + 110ns + 10ns

10ns + 10ns + 10ns for temp_a*2 [10ns for moving 2 into a register, 10ns for multiplication],

110ns for array[ecx],

10ns for mv

9) 10ns for add, 10ns for `ecx` register access

10) 10ns for jmp

Total time taken = sum of (frequency x cost) of all the statements

1) 10*1

3) 30 * 1000000

4) 10 * 1000000

5) 120 * 1000000

6) 20 * 1000000

7) (10 * 500000) + (10 * 1000000)

8) 150 * 500000

9) 20 * 1000000

10) 10 * 1000000

Sum up all the above costs, you will get the answer.

It will equate to 0.175 seconds

7 0

2 years ago

Tiny charts embedded in cells that show a visual trend alongside the data are called __________.

forsale [732]

They are called sparklines

5 0

2 years ago

Create a program that displays a menu to select addition, subtraction, or multiplication. Using random numbers between 0 and 12

Lemur [1.5K]

Answer:

This question is answered using C++

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

int ope, yourresult;

cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

cout<<"Operator: ";

cin>>ope;

srand((unsigned) time(0));

int num1 = rand() % 12;

int num2 = rand() % 12;

int result = 1;

if(ope == 1){

cout<<num1<<" + "<<num2<<" = ";

result = num1 + num2;

}

else if(ope == 2){

cout<<num1<<" - "<<num2<<" = ";

result = num1 - num2;

}

else if(ope == 3){

cout<<num1<<" * "<<num2<<" = ";

result = num1 * num2;

}

else{

cout<<"Invalid Operator";

}

cin>>yourresult;

if(yourresult == result){

cout<<"Correct!";

}

else{

cout<<"Incorrect!";

}

return 0;

}

Explanation:

This line declares operator (ope) and user result (yourresult) as integer

int ope, yourresult;

This prints the menu

cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

This prompts the user for operator

cout<<"Operator: ";

This gets user input for operator

cin>>ope;

This lets the program generates different random numbers

srand((unsigned) time(0));

This generates the first random number

int num1 = rand() % 12;

This generates the second random number

int num2 = rand() % 12;

This initializes result to 1

int result = 1;

If the operator selected is 1 (i.e. addition), this prints an addition operation and calculates the actual result

if(ope == 1){

cout<<num1<<" + "<<num2<<" = ";

result = num1 + num2;

}

If the operator selected is 2 (i.e. subtraction), this prints an subtracttion operation and calculates the actual result

else if(ope == 2){

cout<<num1<<" - "<<num2<<" = ";

result = num1 - num2;

}

If the operator selected is 3 (i.e. multiplication), this prints an multiplication operation and calculates the actual result

else if(ope == 3){

cout<<num1<<" * "<<num2<<" = ";

result = num1 * num2;

}

If selected operator is not 1, 2 or 3, the program prints an invalid operator selector

else{

cout<<"Invalid Operator";

}

This gets user input

cin>>yourresult;

This checks if user result is correct and prints "Correct!"

if(yourresult == result){

cout<<"Correct!";

}

If otherwise, the program prints "Incorrect!"

else{

cout<<"Incorrect!";

}

return 0;

6 0

2 years ago