Select the correct answer from each drop-down menu. Select the correct type of address reference.
2 answers:
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Answer:
Explanation:
The following code is written in Java. It creates the Bug class with the position and direction variables. Then it creates a constructor, move method, turn method, and getPosition method. Finally, a bug object called bugsy is created in the main method, and we move it once to the right, then again to the right, and then we turn it and move it 5 times to the left, printing out the position when it is done moving. Output can be seen in the attached picture below.
class Brainly {
public static void main(String[] args) {
Bug bugsy = new Bug(10);
bugsy.move();
System.out.println("Current bug position: " + bugsy.getPosition());
bugsy.move();
System.out.println("Current bug position: " + bugsy.getPosition());
bugsy.turn();
bugsy.move();
bugsy.move();
bugsy.move();
bugsy.move();
bugsy.move();
System.out.println("Current bug position: " + bugsy.getPosition());
}
}
class Bug {
char direction = 'r';
int position = 0;
public Bug(int initialPosition) {
this.position = initialPosition;
}
public void turn() {
if (this.direction == 'r') {
this.direction = 'l';
} else {
this.direction = 'r';
}
}
public void move() {
if (this.direction == 'r') {
this.position += 1;
} else {
this.position -= 1;
}
}
public int getPosition() {
return this.position;
}
}
Answer:
Following is attached the code that works accordingly as required. It reads in characters from standard input and outputs the number of times it sees an 'a' followed by the letter 'b'. All the description of program is given inside the code as comments.
I hope it will help you!
Explanation:
