All categories

2 years ago

Vertex:Vertex form:

Mathematics

1 answer:

Nonamiya [84]2 years ago

7 0

2.5 and the other form 4

You might be interested in

Can someone please answer some of my questions?<br> *They are all math

Step2247 [10]

Answer:

DA FA WERE ARE THE QUESTIONS?????????

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Identify the maximum and minimum values of the function y = 8 cos x in the interval [-2π, 2π]. Use your understanding of transfo

Lina20 [59]

Pls. see attachment for the answer.

5 0

2 years ago

This is very hard for me , helppp

yarga [219]

<em>The range is 6.25 and the interquartile range is 3.25.</em>

5 0

2 years ago

Read 2 more answers

Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

5 0

2 years ago

What are the solutions of the equation (2x + 3)2 + 3(2x + 3) + 11 = 02 Use u substitution and the quadratic formula to solve.

Stella [2.4K]

Answer:

x=-2.4 or x= - 12/5

Step-by-step explanation:

hope that helps.

8 0

2 years ago

Vertex:Vertex form:​

Vertex:Vertex form: