So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
#SPJ4
Answer:
1.
Variable: x
Inequality: x ≤ 12
Value that matches: 12
2.
Variable: y
Inequality: y < 66
Value that matches: 60
Step-by-step explanation:
Solving (1):
Let x be the variable
Reading through the question, we have the inequality to be represented by "at most".
At most is used for less than or equal to.
Hence, the expression can be represented by:
x ≤ 12
The range of this inequality is limited to all natural number that do not exceed 12.
Examples are 8, 2, 11, 12
Solving (2):
Let the variable be y
Reading through the question, we have the inequality to be represented by "below".
Below means less than
Hence, the expression can be represented by:
y < 66
The range of this inequality is limited to all number less than 66.
Examples are 65, 1 , 60......
293764 would be the answer to this question
Answer:
-4c + 5d
Step-by-step explanation:
3 - 7 = -4, so c is equal to -4.
Since there is only one value for d, d stays the same as 5d.
Answer:
15/8 hours .................
Step-by-step explanation:
Let L be Laura, and B be Ben. Then:
3L=1
5B=1
Next:
15L=5
15B=3
15(L+B)=5+3=8
15/8 (L+B)=1
