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3 years ago

Use the figure below to answer the question. What is the measure of ∠ABC? *

Mathematics

1 answer:

Ronch [10]3 years ago

4 0

Answer:

D 98°

Step-by-step explanation:

180-82 = 98 or the long way

3x+5 = 180-82

3x = 93

x = 31

3(31) + 5 = 98

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So I'm still trying to figure out but tell me. What are two demicals rounded to 1.5

Andrej [43]

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3 years ago

The graph shows the attendance at a hockey game, and the rate at which the fans enter and exit the

Strike441 [17]

Answer:

The answer is below

Step-by-step explanation:

From the graph, we can see that both segment 1 and segment 2 are positive slopes (as the time increases, the number of people increases)

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3 years ago

What property is shown in this equation? (2 X 1/2) + 8 = 1+8

Julli [10]

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3 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

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3 years ago

HELP PLEASE I DONT HAVE MUCH TIME!!!

BaLLatris [955]

Answer:

Step-by-step explanation:

The other answers don't divide into rational numbers

8 0

3 years ago