So for this trinomial, I will be factoring by grouping. Firstly, what two terms have a product of 16x^2 and a sum of 10x? That would be 8x and 2x. Replace 10x with 2x + 8x:
![x^2+2x+8x+16](https://tex.z-dn.net/?f=x%5E2%2B2x%2B8x%2B16)
Next, factor x^2 + 2x and 8x + 16 separately. Make sure that they have the same quantity inside the parentheses: ![x(x+2)+8(x+2)](https://tex.z-dn.net/?f=x%28x%2B2%29%2B8%28x%2B2%29)
<u>Now you can rewrite this as
, which is your final answer.</u>
8t+32 is one expression equivalent to that.
We want to create a linear equation to model the given situation.
A) c(r) = $6.00 + $1.50*r
B) 19 rides.
We know that the carnival charges $6.00 for entry plus $1.50 for each ride.
A) With the given information we can see that if you ride for r rides, then the cost equation will be:
c(r) = $6.00 + $1.50*r
Where c(r) is the cost for going to the carnival and doing r rides.
B) If you have $35.00, then we can solve:
c(r) = $35.00 = $6.00 + $1.50*r
Now we can solve the equation for r.
$35.00 = $6.00 + $1.50*r
$35.00 - $6.00 = $1.50*r
$29.00 = $1.50*r
$29.00/$1.50 = r = 19.33
Rounding to the next whole number we get: r = 19
This means that with $35.00, Dennis could go to 19 rides.
If you want to learn more, you can read:
brainly.com/question/13738061
Answer:
2/36
Step-by-step explanation:
The only outcomes that lead to a sum of 3 are (2,1) and (1,2) therefore there is only a 2 in 36 chance of rolling a sum of 3