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Aloiza [94]
2 years ago
11

50/80 in its simplest form

Mathematics
2 answers:
Lady bird [3.3K]2 years ago
7 0

Answer:

5/8 I belive

Step-by-step explanation:

Hope this helps! ♥

Just divide both by 10

RideAnS [48]2 years ago
6 0

Answer:

5/8 because the simplest fraction of 50/80 is 5/8.

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Try dividing 150 by 2 1/2 and your answer would be 6.25 you may want to double check that math though
4 0
3 years ago
From a tap 60 ml of water is leaked within 5 minutes. Find the wasted amount of water within 2 hours from this tap​
GREYUIT [131]

Answer:

1440 mL

Step-by-step explanation:

2 hours = 120 minutes

120/5 = 24

24 * 60 = 1440

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

6 0
2 years ago
The quotient of 5 less than a number and 6 is -4
Dovator [93]

-1 is the answer  or your answer is gonna be false

7 0
3 years ago
Read 2 more answers
How many times does 5 go into 709?
Sveta_85 [38]
895 times. division!
5 0
3 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
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