C=-160/9+5f/9 I think that's the answer to your qeustion
Answer:
In these situations, the median is generally considered to be the best representative of the central location of the data. The more skewed the distribution, the greater the difference between the median and mean, and the greater emphasis should be placed on using the median as opposed to the mean.
Answer:
1.44
Step-by-step explanation:
1.2*1.2=1.44
So you must set this up as a system of equations
n= noble fir trees
d= douglas fir trees
5n + 3d = $420
12n + 9d = $1,080
To get a positive output you have to multiply the second equation by 3 to be able to be divisable to one another
36n + 18d = 3,240
now divide the equation by 18
2n + d = 180
-2n -2n
d = 180 - 2n
Now put that equation in the first as d ^^^
5n + 3(180 -2n) = 420
5n + 540- 6n = 420
- 540 -540
1n = 120
n = 120
Now put n into the second equation( none changed one) to find d
12(120) + 9d = 3240
1440 + 9d = 3240
-1440 -1440
9d = 1800
÷9 ÷9
d= 200
so the noble is $ 120
and the douglas is $200
Answer:
Third table
Step-by-step explanation:
For the relationship to be proportional
y/x = constant
First table y/x = 8/4 = 2 then 7/11 doesn't =2 so it is not
Second table y/x =52/5 = 5 then 49/7 doesn't =5 so it is not
Third table y/x = 3/6=1/2 then 5/10 = 1/2 then 7/14 = 1/2 it is proportional
Last table y/x = 6/3 = 2 then 11/8 doesn't =2 so it is not